使用java8 stream().map传递两个参数来调用服务方法

Question

我有以下服务正常使用 Java8

List<ReportCount> getReportDetails(List<String> statusList);

statusList.add(Arrays.asList("SUCCESS"));
statusList.add(Arrays.asList("CANCELLED"));    
statusList.add(Arrays.asList("ON_HOLD","INPROGRESS"));

statusList.stream()
          .map(reportService::getReportDetails)
          .forEach(e -> reportMap.put("report_" + reportMap.size(), e));

如何使用上面的代码为下面的方法传递1个参数.

String id="CA";
List<ReportCount> getReportDetails(List<String> statusList, String id);

有谁可以帮忙.谢谢

Answer 1

首先不使用原始类型:

List<ReportCount> getReportDetails(List<String> statusList, String id);

然后使用lambda表达式:

List<List<String>> listOfStatusList = new ArrayList<>();
listOfStatusList.add(Arrays.asList("SUCCESS"));
listOfStatusList.add(Arrays.asList("CANCELLED"));    
listOfStatusList.add(Arrays.asList("ON_HOLD","INPROGRESS"));

String someId = ...;

listOfStatusList.stream()
                .map(statusList -> reportService.getReportDetails(statusList, someId))