Die*_*uza 8 c# asp.net webforms aspxgridview
我在如何通过点击网格视图内的按钮显示模态面板时遇到了很多困难.
上下文:我有一个数据行,其字符串字段可以包含简单文本或base 64编码图像,因此我使用自定义模板来定义何时显示原始内容或按钮"查看图像".此图像将在模式面板上打开,该面板应在按钮单击时上升.
这是我作为控件(ascx)创建的Panel:
<asp:Panel ID="pnlModalOverlay" runat="server" Visible="true" CssClass="Overlay">
<asp:Panel ID="pnlModalMainContent" runat="server" Visible="true" CssClass="ModalWindow">
<div class="WindowTitle">
<asp:Label ID="lbTitle" runat="server" />
</div>
<div class="WindowBody">
<asp:Panel ID="pnlContent" runat="server" Visible="true">
<asp:Image ID="imgContent" runat="server" CssClass="ImageView" />
</asp:Panel>
<div class="Button">
<asp:Button ID="btnOk" runat="server" class="btn btn-default " Text="Close" OnClientClick="loadingPanel.Show();" />
</div>
</div>
</asp:Panel>
</asp:Panel>
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这是我想要使用它的页面和ASPxGridView:
<asp:UpdatePanel ID="UpdatePanel1" runat="server" UpdateMode="Conditional" ChildrenAsTriggers="true">
<ContentTemplate>
<div style="margin-top: 12px;">
<asp:Button type="button" ID="btnShowImage" AutoPostBack="true" class="btn btn-default navbar-right" Text="Show Image"
runat="server" Style="margin-left: 5px;" OnClientClick="loadingGridPanel.Show();" />
</div>
<!-- Some data filter controls -->
<MyWorkspace:AlertModal ID="alertModal" runat="server" Visible="false" />
<MyWorkspace:ImageModal ID="imageModal" runat="server" Visible="false" />
</ContentTemplate>
<Triggers>
<asp:AsyncPostBackTrigger ControlID="mainGrid" />
</Triggers>
</asp:UpdatePanel>
<MyWorkspace:GridViewWrapper ID="mainGrid" runat="server" Visible="true" />
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Codebihind:
public partial class MyPage : System.Web.UI.Page
{
protected override void OnInit(EventArgs e)
{
base.OnInit(e);
btnShowImage.Click += new EventHandler(ShowImage); // This call works fine
}
protected void Page_Load(object sender, EventArgs e)
{
try
{
if (!IsPostBack)
{
mainGrid.CanEditItems = true;
mainGrid.CustomTemplates.Add(new CustomColumnTemplate { columnName = "Id", template = new LinkColumn(CreateParentLink, "Go to parent") });
mainGrid.CustomTemplates.Add(new CustomColumnTemplate { columnName = "Value", template = new ButtonColumn(ShowImage, "View Image") }); // This one doesn't works
}
}
catch (Exception ex)
{
modalAlerta.Show("Page_Load", ex.Message, false, false, "");
}
}
void ShowImage()
{
modalImagem.Show(); // Set Modal's Visible property to True
// UpdatePanel1.Update(); <-- Tryin' force it to work with no success
}
}
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ButtonColumn模板创建:
public class ButtonColumn : System.Web.UI.ITemplate
{
private Action action;
private string controlId;
private string tooltip;
public ButtonColumn(Action onClick, string toolTip)
{
this.action = onClick;
this.controlId= "btnShowImage";
this.tooltip = toolTip;
}
public void InstantiateIn(System.Web.UI.Control container)
{
GridViewDataItemTemplateContainer gridContainer = (GridViewDataItemTemplateContainer)container;
if (System.Text.RegularExpressions.Regex.IsMatch(gridContainer.Text, "^([A-Za-z0-9+/]{4})*([A-Za-z0-9+/]{4}|[A-Za-z0-9+/]{3}=|[A-Za-z0-9+/]{2}==)$"))
{
ImageButton button = new ImageButton();
button.ID = idControle;
button.ImageUrl = "/Images/html5_badge_64.png";
button.Width = 20;
button.Height = 20;
button.ToolTip = tooltip;
button.Click += (s, a) =>
{
if (onClick != null)
onClick();
};
container.Controls.Add(button);
}
else
{
Label label = new Label()
{
Text = gridContainer.Text,
ToolTip = tooltip
};
container.Controls.Add(label);
}
}
}
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点击btnShowImage按钮的方法调用工作正常.但是当我在gridview中通过一个ImageButton(或按钮)执行相同的调用时,它不起作用.两个调用都到达ShowImage方法.
任何帮助,将不胜感激.谢谢你们.
编辑1:
GridView被封装在GridViewWrapper(我使用反射和存储的元数据得到的类的属性的组合动态构建列),这个类有太多的代码在这里分享,我不认为这是原因.此外,我已经在调试模式下执行,并逐步通过它的每一个相关方法.
列添加方法:
CustomColumnTemplate customTemplate = CustomTemplates.FirstOrDefault(f => f.columnName == metadata.ColumnIdName);
gridView.Columns.Add(new GridViewDataColumn()
{
FieldName = metadata.ColumnIdName,
VisibleIndex = GetVisibleIndexByColumnIdName(metadata.ColumnIdName),
Caption = metadata.Caption,
Width = new Unit(DefaultColumnWidth, UnitType.Pixel),
DataItemTemplate = customTemplate == null ? null : customTemplate.template
});
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我已经确定该ShowImage方法正在被击中,但它的行为类似于UpdatePanel1尚未更新
ASPxGridView在ViewState中存储有关列的信息,但不保存有关列模板的信息.这是有目的的,因为模板可能非常复杂,并且它们的序列化使ViewState非常庞大.因此,如果在运行时使用模板创建列,请禁用ViewState:
ASPxGridView.EnableViewState="false"
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并在每个回调上创建列:
//if (!IsPostBack)
//{
mainGrid.CanEditItems = true;
mainGrid.CustomTemplates.Add(new CustomColumnTemplate { columnName = "Id", template = new LinkColumn(CreateParentLink, "Go to parent") });
mainGrid.CustomTemplates.Add(new CustomColumnTemplate { columnName = "Value", template = new ButtonColumn(ShowImage, "View Image") }); // This one doesn't works
//}
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