通过vuejs中的变量动态调用方法

Question

是否可以通过变量调用方法？我有拖放具有ID的元素,根据id我必须调用该方法.考虑以下例子.

<template>
   <div>
    <div id="draggable">
      <div class="draggable" id="db">Step2</div>
      <div class="draggable" id="spstep"> Step</div>
      <div class="draggable" id="merge">Merge</div>
      <div class="draggable" id="copy">copy</div>
    </div>
     <div id="id="draggable"">Drop Here</div>
   </div>
 </template> 

<script>
  export default {

  data () {

   }
  mounted () {
  var _this = this
  $(".draggable").draggable({
     grid: [ 20, 20 ],
     appendTo: '#droppable',
     // containment: "window",
     cursor: 'move',
     revertDuration: 100,
     revert: 'invalid',
     helper: 'clone',
     refreshPositions: true,
     scroll: true,
     containment: "document",
      zIndex: 10000,
 });

 $("#droppable").droppable({
     accept: ".draggable",
     tolerance: "intersect",
     drop: function (event, ui) {         
       var leftPosition  = pos.left;//ui.offset.left - $(this).offset().left;
       var topPosition   = pos.top;//ui.offset.top - $(this).offset().top;
       console.log(leftPosition + "  "+ topPosition);
       var type = ui.draggable.attr("id");

       //Here call methods according to id of draggable element
       //like 
       //current implement which is not enhanced code
       if(type == 'db')
          _this.db()

       if(type == 'spstep')
          _this.spstep()

       if(type == 'merge')
          _this.merge()

       if(type == 'copy')
          _this.copy()   
        //desired implementation alike
        _this.[type]() // this syntax is wrong and throws an error  
       }
     }); 
 }
 methods: {
  db(){
    //db called do something
  }
  spstep(){
    //spstep called do something
  }
  merge(){
    //merge called do something
  }
  copy(){
    //copy called do something
  }
}
</script>
<style>
</style>

上面是我的示例代码,其中我在comments中提到了我的要求.我想根据拖动元素调用方法.我不知道这是可能的,但通过这种方法,我可以减少许多不需要的代码.

任何帮助将非常感谢
谢谢

Answer 1

在Javascript中,如果你是这样的对象:

const foo = {
    bar() {},
    baz() {}
};

要"动态地"调用它,你应该输入

foo['bar']()
foo['baz']()

所以,在你的情况下,而不是:

this.[type]()

你应该输入:

this[type]()

对象可以像数组索引一样进行操作,但在这种情况下,索引是字段

警告:您的$.droppable().drop功能未正确绑定.那么,此时,this不是VueJS组件:

• 在基础知识vuejs组件的函数/方法中使用es6函数字段(如挂载的......).
• 在这个函数中,使用箭头函数来为正确的上下文提供支持this.在此示例中,您的drop函数必须是箭头函数才能正常工作