如何使用hibernate在spring boot中调用MySQL存储过程？

Question

我在MySQL存储过程中编写了一些逻辑.我正在使用带有hibernate的spring boot.我有一个IN OUT参数的登录程序.从我的登录程序,我想传递给用户的消息.但我不知道如何在Spring启动时调用存储过程.我的代码如下:

1. 我的登录程序是

   CREATE PROCEDURE login(IN  in_user_id    varchar(100),
                              IN  in_password   varchar(100),
                              OUT out_code      INT,
                              OUT out_message   varchar(100))
    BEGIN
       IF in_user_id IS NULL OR in_user_id = ''
        THEN
        SET out_code = 1;
        SET out_message = 'Please Enter Your First Name.';
      END IF;
    /*Logi Here*/
   
    END;
   

2. 我曾经使用过实体类

   @Entity
   @Table(name = "user")
    @NamedStoredProcedureQueries({
      @NamedStoredProcedureQuery(
      name = "do_login", 
      procedureName = "login", 
      resultClasses = { LoginModel.class },    
      parameters = { 
         @StoredProcedureParameter( name = " in_user_id",  type = String.class,  mode = ParameterMode.IN),
         @StoredProcedureParameter( name = "in_password",  type = String.class,  mode = ParameterMode.IN),
         @StoredProcedureParameter( name = "out_code",  type = Integer.class,  mode = ParameterMode.OUT), 
         @StoredProcedureParameter( name = "out_message",  type = String.class,  mode = ParameterMode.OUT)
   
        }),
   
    })
   
    public class LoginModel implements Serializable {
   
      @NotEmpty
      private String userid;
   
      @NotEmpty
      private String password;
   
     //Here is getter setter
     }
   

3. 在我的登录控制器中,我想调用我的程序,以便我可以将我的用户转发到仪表板.如果用户输入错误的用户ID或密码,我想显示来自程序的消息.我在登录控制器中使用了波纹管代码

   @RequestMapping(value = "/login", method = RequestMethod.POST)
    public String doLogin(@ModelAttribute("webLoginForm") @Valid LoginModel registrationModel,
       BindingResult bindingResult, Model model, Errors error) {
        if(error.hasErrors()) {
            return "login";
        }
   
      // Here I want to check My Procedure result & redirect to welcome page
      //return "redirect:/welcome";
   
     return "login";
   }
   

4. 我使用过存储库,但它没有在这里写任何东西.我曾经使用过仓库像..

      public interface LoginRepository  extends CrudRepository<LoginModel, Integer>{
   
   
    }
   

Answer 1

您可以使用javax.persistence.StoredProcedureQuery调用存储过程.你甚至不需要在你的实体上申报任何东西.
我建议将过程调用逻辑移动到服务,然后从控制器调用服务方法.

例如:

@Service
public class LoginServiceImpl implements LoginService {

    @PersistenceContext
    private EntityManager entityManager;

    public Boolean checkUsernameAndPassword(String username, String password) {

        //"login" this is the name of your procedure
        StoredProcedureQuery query = entityManager.createStoredProcedureQuery("login"); 

        //Declare the parameters in the same order
        query.registerStoredProcedureParameter(1, String.class, ParameterMode.IN);
        query.registerStoredProcedureParameter(2, String.class, ParameterMode.IN);
        query.registerStoredProcedureParameter(3, Integer.class, ParameterMode.OUT);
        query.registerStoredProcedureParameter(4, String.class, ParameterMode.OUT);

        //Pass the parameter values
        query.setParameter(1, username);
        query.setParameter(2, password);

        //Execute query
        query.execute();

        //Get output parameters
        Integer outCode = (Integer) query.getOutputParameterValue(3);
        String outMessage = (String) query.getOutputParameterValue(4);

        return true; //enter your condition
    }
}

然后,您可以在注入之后从Controller中调用此方法LoginService.