C#通过枚举迭代？(索引System.Array)

Question

我有以下代码:

// Obtain the string names of all the elements within myEnum 
String[] names = Enum.GetNames( typeof( myEnum ) );

// Obtain the values of all the elements within myEnum 
Array values = Enum.GetValues( typeof( myEnum ) );

// Print the names and values to file
for ( int i = 0; i < names.Length; i++ )
{
    print( names[i], values[i] ); 
}

但是,我无法索引值.有更简单的方法吗？

或者我完全错过了什么!

Answer 1

Array values = Enum.GetValues(typeof(myEnum));

foreach( MyEnum val in values )
{
   Console.WriteLine (String.Format("{0}: {1}", Enum.GetName(typeof(MyEnum), val), val));
}

或者,您可以强制转换返回的System.Array:

string[] names = Enum.GetNames(typeof(MyEnum));
MyEnum[] values = (MyEnum[])Enum.GetValues(typeof(MyEnum));

for( int i = 0; i < names.Length; i++ )
{
    print(names[i], values[i]);
}

但是,你能确定GetValues以与GetNames返回名称相同的顺序返回值吗？

Answer 2

你需要强制转换数组 - 返回的数组实际上是所请求的类型,即myEnum[]如果你要求typeof(myEnum):

myEnum[] values = (myEnum[]) Enum.GetValues(typeof(myEnum));

然后values[0]等

Answer 3

您可以将该数组转换为不同类型的数组:

myEnum[] values = (myEnum[])Enum.GetValues(typeof(myEnum));

或者如果你想要整数值:

int[] values = (int[])Enum.GetValues(typeof(myEnum));

你可以迭代那些铸造的数组当然:)

Answer 4

字典列表怎么样？

Dictionary<string, int> list = new Dictionary<string, int>();
foreach( var item in Enum.GetNames(typeof(MyEnum)) )
{
    list.Add(item, (int)Enum.Parse(typeof(MyEnum), item));
}

当然,您可以将字典值类型更改为您的枚举值.

Answer 5

另一个解决方案,有趣的可能:

enum Days { Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday }

static class Helpers
{
public static IEnumerable<Days> AllDays(Days First)
{
  if (First == Days.Monday)
  {
     yield return Days.Monday;
     yield return Days.Tuesday;
     yield return Days.Wednesday;
     yield return Days.Thursday;
     yield return Days.Friday;
     yield return Days.Saturday;
     yield return Days.Sunday;
  } 

  if (First == Days.Saturday)
  {
     yield return Days.Saturday;
     yield return Days.Sunday;
     yield return Days.Monday;
     yield return Days.Tuesday;
     yield return Days.Wednesday;
     yield return Days.Thursday;
     yield return Days.Friday;
  } 
}