我有以下工作职能:
unMaybe : (t : Type) -> {auto p : t = Maybe x} -> Type
unMaybe {x} _ = x
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这个功能很好用:
> unMaybe (Maybe Int)
Int
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我还有另一个类似的功能:
unMaybesA : (ts : Vect n Type) -> {xs : Vect n Type} -> {auto p : map Maybe xs = ts} -> Vect n Type
unMaybesA {xs} _ = xs
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不幸的是,以下失败:
> unMaybesA [Maybe Int, Maybe String]
(input):1:1-35:When checking argument p to function Main.unMaybesA:
Can't find a value of type
Data.Vect.Vect n implementation of Prelude.Functor.Functor, method map Maybe
xs =
[Maybe Int, Maybe String]
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但以下工作:
> unMaybesA {xs=[_,_]} [Maybe Int, Maybe String]
[Int, String]
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这是一种让Idris能够自动{xs=[_,_]}处理_矢量的方法吗?
unMaybesB : (ts : Vect n Type) -> {auto p : (xs : Vect n Type ** map Maybe xs = ts)} -> Vect n Type
unMaybesB {p} _ = fst p
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可能通过使用elaborator脚本在上面的函数中自动填充p?
我在下面列出了一个详细的脚本.我只需要弄清楚如何从目标中生成n,ts和xs.
helper1 : Vect n Type -> Vect n Type -> Type
helper1 ts xs = (map Maybe xs) = ts
unMaybesC : (ts : Vect n Type) -> {auto p : DPair (Vect n Type) (helper1 ts)} -> Vect n Type
unMaybesC {p} _ = fst p
helper2 : (n : Nat) -> (ts : Vect n Type) -> (xs : Vect n Type) -> helper1 ts xs -> DPair (Vect n Type) (helper1 ts)
helper2 _ _ xs p = MkDPair xs p
q : Elab ()
q = do
let n = the Raw `(2 : Nat)
let ts = the Raw `(with Vect [Maybe String, Maybe Int])
let xs = the Raw `(with Vect [String, Int])
fill `(helper2 ~n ~ts ~xs Refl)
solve
qC : Vect 2 Type
qC = unMaybesC {p=%runElab q} [Maybe String, Maybe Int]
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map Maybe xs = ts看似惯用,但很难.如果要auto搜索非简单证明,请编写显式证明类型.然后,证明搜索将尝试构造函数并在正确的方向上引导.
data IsMaybes : Vect n Type -> Vect n Type -> Type where
None : IsMaybes [] []
Then : IsMaybes xs ms -> IsMaybes (t :: xs) (Maybe t :: ms)
unMaybes : (ts : Vect n Type) -> {xs : Vect n Type} -> {auto p : IsMaybes xs ts} -> Vect n Type
unMaybes ts {xs} = xs
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有了这个:
> unMaybes [Maybe Nat, Maybe Int, Maybe (Maybe String)]
[Nat, Int, Maybe String] : Vect 3 Type
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