SQL Server 2016中JSON数据的where子句

Har*_*m M 5 sql-server json sql-server-2016 sql-server-json json-query

我的表中有一个nvarchar(1000)字段,并且正在该列中存储JSON数据。

例如:

 CONTENT_RULE_ID    CONTENT_RULE
 1                  {"EntityType":"Inquiry", "Values":[1,2]}
 2                  {"EntityType":"Inquiry", "Values":[1,3]}
 3                  {"EntityType":"Inquiry", "Values":[2,4]}
 4                  {"EntityType":"Inquiry", "Values":[5,6,1]}
 6                  {"EntityType":"Inquiry", "Values":[8,1]}
 8                  {"EntityType":"Inquiry", "Values":[10,12,11]}
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由此我如何在sql server中使用JSON_QUERY获取所有查询ID为1的CONTENT_RULE_ID

Era*_*per 2

@Harisyam,您可以尝试以下查询吗

declare @val int = 1

;with cte as (
    select *
    from CONTENT_RULES
    cross apply openjson (CONTENT_RULE, '$')
), list as (
    select 
    CONTENT_RULE_ID, replace(replace([value],'[',''),']','') as [value]
    from cte 
    where CONTENT_RULE_ID in (
    select CONTENT_RULE_ID
    from cte 
    where [key] = 'EntityType' and [value] = 'Inquiry'
    ) 
    and [key] = 'Values'
)
select 
CONTENT_RULE_ID, s.value
from list
cross apply string_split([value],',') s
where s.value = @val
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我使用SQL string_split函数来一一获取查询值

输出是

在此输入图像描述

第二个查询可以跟随一个查询

select
    CONTENT_RULE_ID
from CONTENT_RULES
cross apply openjson (CONTENT_RULE, '$')
where replace(replace(value,'[',','),']',',') like '%,1,%'
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也许需要 OpenJSON 支持的最完整的 SQL 查询如下

select
    content_rule_id,
    [value]
from Content as c
cross apply openjson(c.CONTENT_RULE, '$') with (
    EntityType nvarchar(100),
    [Values] nvarchar(max) as json
) as e
cross apply openjson([Values], '$') as v
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