如何将参数传递给gtest

Question

如何将参数传递给我的测试套件？

gtest --number-of-input=5

我有以下主要的gtest代码.并且--number-of-input=5应该传递给InitGoogleTest().

#include <iostream>
#include <gtest/gtest.h>

int main(int argc, char **argv) {
  std::cout << "Running main() from gtest_main.cc\n";
  ::testing::GTEST_FLAG(output) = "xml:hello.xml";
  testing::InitGoogleTest(&argc, argv);

  return RUN_ALL_TESTS();
}

我不知道如何将我的参数传递给测试套件/案例如下？

class TestTwo : public QuickTest {
 protected:
  virtual void SetUp() {
      QuickTest::SetUp();
      square = new Square(10);
      circle = new Circle(10);

  }

  virtual void TearDown() {
      delete square;
      delete circle;
      QuickTest::TearDown();
  }

  Square* square;
  Circle* circle;
};


// Now, let's write tests using the QueueTest fixture.

// Tests the default constructor.
TEST_F(TestOne, DefaultConstructor) {
  EXPECT_EQ(100.0, square->area());
}
TEST_F(TestOne, DefaultDestructor) {
  EXPECT_EQ(1,1);
}
TEST_F(TestOne, VHDL_EMIT_Passthrough) {
  EXPECT_EQ(1,1);
}
TEST_F(TestOne, VHDL_BUILD_Passthrough) {
  EXPECT_EQ(1,1);
}

添加

我修改了main方法以显示之后的argv [i] InitGoogleTest().

int main(int argc, char **argv) {
    std::cout << "Running main() from gtest_main.cc\n";
    ::testing::GTEST_FLAG(output) = "xml:hello.xml";
    testing::InitGoogleTest(&argc, argv);

    for (int i = 0; i < argc; i++) {
        cout << i << ":" << argv[i] << endl;
    }

这是给予gtest的论据:./s --number-of-input=5 --gtest_filter=Test_Cases1*.

这是结果:

Running main() from gtest_main.cc
0:./s
1:--number-of-input=5
Note: Google Test filter = Test_Cases1*
[==========] Running 0 tests from 0 test cases.
[==========] 0 tests from 0 test cases ran. (0 ms total)
[  PASSED  ] 0 tests.

gtest过滤掉没有名称的测试,Test_Cases1它还显示除了那些开头的正确参数gtest.

参考 - 如何在GoogleTest中运行特定的测试用例

Answer 1

Google Test仅识别自己的命令行选项.每次找到一个,它都会从中删除argv并相应地更新argc,因此在InitGoogleTest返回后,剩下的任何内容argv都可供您自行处理.使用您最喜欢的命令行解析技术,将结果存储在某个全局变量中,并在测试期间引用它.

如果命令行选项看起来像 Google测试选项但实际上不是,那么程序将打印其帮助消息并退出而不运行任何测试.Google测试选项始于gtest_.