我试图取代的所有实例href="../directory"用href="../directory/index.html".
在Python中,这个
reg = re.compile(r'<a href="../(.*?)">')
for match in re.findall(reg, input_html):
output_html = input_html.replace(match, match+'index.html')
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产生以下输出:
href="../personal-autonomy/index.htmlindex.htmlindex.htmlindex.html"
href="../paternalism/index.html"
href="../principle-beneficence/index.htmlindex.htmlindex.html"
href="../decision-capacity/index.htmlindex.htmlindex.html"
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知道为什么它适用于第二个链接,但其他链接不适用?
相关部分来源:
<p>
<a href="../personal-autonomy/">autonomy: personal</a> |
<a href="../principle-beneficence/">beneficence, principle of</a> |
<a href="../decision-capacity/">decision-making capacity</a> |
<a href="../legal-obligation/">legal obligation and authority</a> |
<a href="../paternalism/">paternalism</a> |
<a href="../identity-personal/">personal identity</a> |
<a href="../identity-ethics/">personal identity: and ethics</a> |
<a href="../respect/">respect</a> |
<a href="../well-being/">well-being</a>
</p>
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编辑:重复的'index.html'实际上是多个匹配的结果.(例如,href ="../ personal-autonomy/index.htmlindex.htmlindex.htmlindex.html"是因为../personal-autonomy在原始源中被找到四次).
作为一般的正则表达式问题,如何在不向所有匹配项添加额外"index.html"的情况下替换所有实例?
import re
from lxml import html
def replace_link(link):
if re.match(r"\.\./[^/]+/$", link):
link += "index.html"
return link
print html.rewrite_links(your_html_text, replace_link)
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<p>
<a href="../personal-autonomy/index.html">autonomy: personal</a> |
<a href="../principle-beneficence/index.html">beneficence, principle of</a> |
<a href="../decision-capacity/index.html">decision-making capacity</a> |
<a href="../legal-obligation/index.html">legal obligation and authority</a> |
<a href="../paternalism/index.html">paternalism</a> |
<a href="../identity-personal/index.html">personal identity</a> |
<a href="../identity-ethics/index.html">personal identity: and ethics</a> |
<a href="../respect/index.html">respect</a> |
<a href="../well-being/index.html">well-being</a>
</p>
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