sag*_*uri 7 android android-edittext android-inputtype
我有一个EditText谁inputType是numberPassword.我想更改替换文本的点大小.它对我来说非常小(android默认).我想增加点大小.我怎样才能做到这一点?
尝试用这个ascii代码替换星号.
⚫ - ⚫ - 中黑圈⬤ - ⬤ - 黑色大圆圈
public class MyPasswordTransformationMethod extends PasswordTransformationMethod {
@Override
public CharSequence getTransformation(CharSequence source, View view) {
return new PasswordCharSequence(source);
}
private class PasswordCharSequence implements CharSequence {
private CharSequence mSource;
public PasswordCharSequence(CharSequence source) {
mSource = source; // Store char sequence
}
public char charAt(int index) {
return '*'; // This is the important part
}
public int length() {
return mSource.length(); // Return default
}
public CharSequence subSequence(int start, int end) {
return mSource.subSequence(start, end); // Return default
}
}
};
text.setTransformationMethod(new MyPasswordTransformationMethod());
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解决方案提供了一半的工作,问题是该转换会将文本直接转换为“*”,而预期的行为是在输入新字符后或几秒钟后隐藏字符,以便用户有机会在隐藏之前看到真正的字符。如果你想保持默认行为,你应该做这样的事情:
/**
* A transformation to increase the size of the dots displayed in the text.
*/
private object BiggerDotPasswordTransformationMethod : PasswordTransformationMethod() {
override fun getTransformation(source: CharSequence, view: View): CharSequence {
return PasswordCharSequence(super.getTransformation(source, view))
}
private class PasswordCharSequence(
val transformation: CharSequence
) : CharSequence by transformation {
override fun get(index: Int): Char = if (transformation[index] == DOT) {
BIGGER_DOT
} else {
transformation[index]
}
}
private const val DOT = '\u2022'
private const val BIGGER_DOT = '?'
}
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这将用您想要的任何字符替换原始点。
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