如何使用十进制变量

Question

我正在使用For循环来循环包含百分比的数组中的变量.对于每个值,我通过一个等式给出了所有百分比的平均值.唯一的问题是我不确定如何更改变量类型以容纳小数,同时也可以使用我的方程式.

// Calculate average of all percentages for specific exercise
long totalNumber = 0;
int temp;
long numberOfObjects = [iterationArray count];
for (NSArray *object in iterationArray) {
    temp = [(NSNumber *)[object objectAtIndex:4] intValue]/100;
    totalNumber = totalNumber + temp;
}
exercisePercentage = (totalNumber/numberOfObjects)*100;

return exercisePercentage;

我知道这temp是需要小数的变量.我正在考虑使用NSDecimalNumber但不知道如何适应其余的代码来返回long值.

尽管事实上是80 ,但我已经尝试过制造一个double或者float两个都返回0 .temp = [(NSNumber *)[object objectAtIndex:4] intValue]/100;[(NSNumber *)[object objectAtIndex:4] intValue]

Answer 1

使用int除以int总是返回int,所以你需要将一个值转换为float或double,如下所示:

// Calculate average of all percentages for specific exercise
double totalNumber = 0.0;
double temp;
long numberOfObjects = [iterationArray count];
for (NSArray *object in iterationArray) {
    temp = [(NSNumber *)[object objectAtIndex:4] intValue]/100.0;
    totalNumber = totalNumber + temp;
}
exercisePercentage = (totalNumber/numberOfObjects)*100.0;

return exercisePercentage;

看它是100.0,现在它应该工作.