我们如何使用python flask从另一个路由中调用带有参数的路由?

pur*_*ram 4 html python flask python-2.7 python-requests

我正在发布一种形式,其中有两个输入到python flask路由。

  <form action = "http://localhost:5000/xyz" method = "POST">
     <p>x <input type = "text" name = "x" /></p>
     <p>y <input type = "text" name = "y" /></p>
     <p><input type = "submit" value = "submit" /></p>
  </form>
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python flask代码就像。

@app.route('/xyz', methods = ['POST', 'GET'])
def xyz():
    if request.method == 'POST':
       x = request.form["x"]
       y = request.form["y"]
       callonemethod(x,y)
    return render_template('index.html', var1=var1, var2=var2)
       #abc(x,y) #can i call abc() like this .i want to call abc() immediately, as it is streaming log of callonemethod(x,y) in console.

@app.route('/abc', methods = ['POST', 'GET'])       
def abc():
    callanothermethod(x,y)
    return render_template('index.html', var1=var3, var2=var4)
    #I want to use that x, y here. also want to call abc() whenever i call xyz()
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如何使用python flask从另一个路由调用带有参数的路由?

mat*_*yas 5

您有两个选择:
选择1:使用从路由中获得的参数进行重定向:

import os
from flask import Flask, redirect, url_for

@app.route('/abc/<x>/<y>')
def abc(x, y):
  callanothermethod(x,y)
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然后您可以将调用的网址重定向到上面的他的路由,如下所示:

@app.route('/xyz', methods = ['POST', 'GET'])
def xyz():
    if request.method == 'POST':
       x = request.form["x"]
       y = request.form["y"]
       callonemethod(x,y)
       return redirect(url_for('abc', x=x, y=y))
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另请参阅有关Flask中的重定向的文档

选项2:
似乎从多个不同位置调用了abc方法。这可能意味着将其从视图中解封装可能是一个好主意:

utils.py
from other_module import callanothermethod
def abc(x, y):
  callanothermethod(x,y)

import os
from flask import Flask, redirect, url_for
from utils import abc

@app.route('/abc/<x>/<y>')
def abc_route(x, y):
  callanothermethod(x,y)
  abc(x, y)

@app.route('/xyz', methods = ['POST', 'GET'])
def xyz():
    if request.method == 'POST':
       x = request.form["x"]
       y = request.form["y"]
       callonemethod(x,y)
       abc(x, y)
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  • 那么选项2呢?您可以解耦 abc() 方法并从两个路由中调用。 (2认同)