Bok*_*oky 2 python django json
我有一个Django模型,如下所示:
class BodyHeight(models.Model):
seats = models.ForeignKey(to=Seats)
name = models.CharField(max_length=127, null=True, blank=True)
key = models.CharField(max_length=100, null=True)
data = models.TextField(null=True, blank=True)
class Meta:
verbose_name_plural = "Body heights"
def __str__(self):
return self.name
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然后在data字段中存储json数据,如下所示:
{"url": "https://some_url=/BE?category=COMMERCIAL, "images": ["url_to_some_image"]}
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我想仅在Django管理面板中显示该字段的网址。
我现在有:
class BodyHeightAdmin(admin.ModelAdmin):
search_fields = ('name', )
list_display = ('id', 'name', 'key', )
list_display_links = ('id', 'name', 'key', )
admin.site.register(BodyHeight, BodyHeightAdmin)
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那是没有数据字段。如果我data在list_display其中添加的字段显示的是整个json(丑陋的格式),但我只想要url。
任何想法如何做到这一点?
我改变了bodyHeightAdmin类如下:
class BodyHeightAdmin(admin.ModelAdmin):
search_fields = ('name', )
list_display = ('id', 'name', 'key', 'url', )
list_display_links = ('id', 'name', 'key', )
def url(self, instance):
data = json.loads(instance.data)
return data["url"]
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它奏效了。
我在Django Admin中为JSONField添加基本格式的解决方案:
import json
import logging
from django.contrib import admin
from django.contrib.postgres.fields import JSONField
from django.forms import widgets
logger = logging.getLogger(__name__)
class PrettyJSONWidget(widgets.Textarea):
def format_value(self, value):
try:
value = json.dumps(json.loads(value), indent=2, sort_keys=True)
# these lines will try to adjust size of TextArea to fit to content
row_lengths = [len(r) for r in value.split('\n')]
self.attrs['rows'] = min(max(len(row_lengths) + 2, 10), 30)
self.attrs['cols'] = min(max(max(row_lengths) + 2, 40), 120)
return value
except Exception as e:
logger.warning("Error while formatting JSON: {}".format(e))
return super(PrettyJSONWidget, self).format_value(value)
class JsonAdmin(admin.ModelAdmin):
formfield_overrides = {
JSONField: {'widget': PrettyJSONWidget}
}
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用法:
admin.site.register(models.MyModel, JsonAdmin)
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希望对您有帮助!
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