好的.我已经设置了一小组样本表.我只是举个例子,因为这是我能够传达问题的最佳方式.
证书表:
WorkerId Name Version
----------- -------------------------------- -----------
1 Construction 1
1 Construction 2
1 Demolition 1
1 Fusion 1
5 Fusion 1
4 Demolition 1
4 Demolition 2
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CertDesc表(版本,名称形式主键):
Name Version Description
-------------------------------- ----------- -----------------------------------------------------------------------------------------
Construction 1 Basic Construction -- Required for all construction workers.
Construction 2 Full Construction -- Required for all construction managers.
Demolition 1 Demolition -- Explosives -- Required for demolition managers.
Fusion 1 Fusion System Control -- Includes catastrophic super-criticality recovery.
Demolition 2 Large Scale Demolition -- Basic fission knowledge with full chemical cert.
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现在.我想获得所有CertDesc行的列表,以便WorkerId 1没有该证书.对于X = 1,我应该只获得拆迁2.
这是对我来说最好的查询:
Select Distinct d.Name, d.Version, d.Description
From CertDesc d join Certs c on d.Name = c.Name and d.Version = c.Version
Where d.Name NOT IN (Select c2.Name
From Certs c2
Where c2.WorkerId = 1)
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此查询返回零行.问题是,无论版本号如何,都会排除拆除行.我想要的是使用IN与元组:
Select Distinct d.Name, d.Version, d.Description
From CertDesc d join Certs c on d.Name = c.Name and d.Version = c.Version
Where (d.Name, d.Version) NOT IN (Select c2.Name, c2.Version)
From Certs c2
Where c2.WorkerId = 1)
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不幸的是,这在SQL Server中无效.有人知道一个很好的方法吗?
SELECT *
FROM CertDesc cd
WHERE NOT EXISTS
(
SELECT NULL
FROM Certs c
WHERE c.WorkerId = 1
AND c.name = cd.name
AND c.version = cd.version
)
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,或者,如果name并且version足够,就这样:
SELECT name, version
FROM CertDesc
EXCEPT
SELECT name, version
FROM Certs
WHERE WorkerId = 1
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编辑:后一个查询仅适用于SQL-Server 2005.