Kev*_*izu 1 swift dispatch-queue
我有一个用于introViewController的DispatchQueue,它显示一个11秒的gif然后显示我的登录页面......但是还有一个跳过介绍并显示登录的按钮.当我点击它时,仍在运行的时间和当我在应用程序中导航时,在时间结束时返回登录.
这是我的班级
class GifClass: UIViewController {
@IBOutlet weak var gifImage: UIImageView!
@IBOutlet weak var skipButton: UIButton!
override func viewDidLoad() {
super.viewDidLoad()
gifImage.loadGif(name: "promed")
DispatchQueue.main.asyncAfter(deadline: .now() + .seconds(11)) {
self.performSegue(withIdentifier: "introLogin", sender: self)
}
}
@IBAction func skip(_ sender: Any) {
performSegue(withIdentifier: "introLogin", sender: self)
}
}
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如何点击按钮停止时间?
Dan*_*all 11
为此,您可以使用DispatchWorkItem
.这是参考:
https://developer.apple.com/documentation/dispatch/dispatchworkitem
这是一个如何在代码中使用它的示例:
class GifClass: UIViewController {
@IBOutlet weak var gifImage: UIImageView!
@IBOutlet weak var skipButton: UIButton!
private var workItem: DispatchWorkItem? // Create a private DispatchWorkItem property
override func viewDidLoad() {
super.viewDidLoad()
gifImage.loadGif(name: "promed")
workItem = { // Set the work item with the block you want to execute
self.performSegue(withIdentifier: "introLogin", sender: self)
}
DispatchQueue.main.asyncAfter(deadline: .now() + .seconds(11), execute: workItem!)
}
@IBAction func skip(_ sender: Any) {
workItem?.cancel() // Cancel the work item in the queue so it doesn't run
performSegue(withIdentifier: "introLogin", sender: self)
}
}
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我不确定这里是否有最佳实践,但我会考虑使用计时器而不是 DispatchQueue 来完成您正在做的事情。
class GifClass: UIViewController {
@IBOutlet weak var gifImage: UIImageView!
@IBOutlet weak var skipButton: UIButton!
var timer = Timer()
override func viewDidLoad() {
super.viewDidLoad()
gifImage.loadGif(name: "promed")
timer = Timer.scheduledTimer(timeInterval: 11, target: self, selector: #selector(timerAction), userInfo: nil, repeats: false)
}
@objc func timerAction() {
performSegue(withIdentifier: "introLogin", sender: self)
}
@IBAction func skip(_ sender: Any) {
timer.invalidate()
performSegue(withIdentifier: "introLogin", sender: self)
}
}
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