tin*_*ker 1 arrays assert slice rust
我已经编写了一些测试,我需要声明两个数组相等.有些阵列[u8; 48]而有些则是[u8; 188]:
#[test]
fn mul() {
let mut t1: [u8; 48] = [0; 48];
let t2: [u8; 48] = [0; 48];
// some computation goes here.
assert_eq!(t1, t2, "\nExpected\n{:?}\nfound\n{:?}", t2, t1);
}
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我在这里收到多个错误:
error[E0369]: binary operation `==` cannot be applied to type `[u8; 48]`
--> src/main.rs:8:5
|
8 | assert_eq!(t1, t2, "\nExpected\n{:?}\nfound\n{:?}", t2, t1);
| ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
|
= note: an implementation of `std::cmp::PartialEq` might be missing for `[u8; 48]`
= note: this error originates in a macro outside of the current crate (in Nightly builds, run with -Z external-macro-backtrace for more info)
error[E0277]: the trait bound `[u8; 48]: std::fmt::Debug` is not satisfied
--> src/main.rs:8:57
|
8 | assert_eq!(t1, t2, "\nExpected\n{:?}\nfound\n{:?}", t2, t1);
| ^^ `[u8; 48]` cannot be formatted using `:?`; if it is defined in your crate, add `#[derive(Debug)]` or manually implement it
|
= help: the trait `std::fmt::Debug` is not implemented for `[u8; 48]`
= note: required by `std::fmt::Debug::fmt`
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试图将它们打印为像t2[..]或t1[..]似乎不起作用的切片.
如何使用assert这些数组并打印它们?
作为一种解决方法,您可以使用&t1[..](而不是t1[..])将数组转换为切片.您必须为比较和格式化执行此操作.
assert_eq!(&t1[..], &t2[..], "\nExpected\n{:?}\nfound\n{:?}", &t2[..], &t1[..]);
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要么
assert_eq!(t1[..], t2[..], "\nExpected\n{:?}\nfound\n{:?}", &t2[..], &t1[..]);
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理想情况下,原始代码应该编译,但现在不行.原因是由于缺少const泛型,标准库为最多32个元素的数组实现了共同的特征(例如Eq和Debug).
因此,您可以比较和格式化较短的数组,如:
let t1: [u8; 32] = [0; 32];
let t2: [u8; 32] = [1; 32];
assert_eq!(t1, t2, "\nExpected\n{:?}\nfound\n{:?}", t2, t1);
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使用Iterator::eq,可以比较任何可以变成相等迭代器的东西:
let mut t1: [u8; 48] = [0; 48];
let t2: [u8; 48] = [0; 48];
assert!(t1.iter().eq(t2.iter()));
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对于比较部分,您可以将数组转换为迭代器并进行元素比较.
assert_eq!(t1.len(), t2.len(), "Arrays don't have the same length");
assert!(t1.iter().zip(t2.iter()).all(|(a,b)| a == b), "Arrays are not equal");
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