use*_*782 7 derby sbt apache-spark
我有一个简单的火花功能来测试DF窗口:
import org.apache.spark.sql.{DataFrame, SparkSession}
object ScratchPad {
def main(args: Array[String]): Unit = {
val spark = SparkSession.builder().master("local[*]").getOrCreate()
spark.sparkContext.setLogLevel("ERROR")
get_data_frame(spark).show()
}
def get_data_frame(spark: SparkSession): DataFrame = {
import spark.sqlContext.implicits._
val hr = spark.sparkContext.parallelize(List(
("Steinbeck", "Sales", 100),
("Woolf", "IT", 99),
("Wodehouse", "Sales", 250),
("Hemingway", "IT", 349)
)
).toDF("emp", "dept", "sal")
import org.apache.spark.sql.expressions.Window
import org.apache.spark.sql.functions._
val windowspec = Window.partitionBy($"dept").orderBy($"sal".desc)
hr.withColumn("rank", row_number().over(windowspec))
}
}
Run Code Online (Sandbox Code Playgroud)
我写了一个像这样的测试:
import com.holdenkarau.spark.testing.DataFrameSuiteBase
import org.apache.spark.sql.Row
import org.apache.spark.sql.types._
import org.scalatest.FunSuite
class TestDF extends FunSuite with DataFrameSuiteBase {
test ("DFs equal") {
val expected=sc.parallelize(List(
Row("Wodehouse","Sales",250,1),
Row("Steinbeck","Sales",100,2),
Row("Hemingway","IT",349,1),
Row("Woolf","IT",99,2)
))
val schema=StructType(
List(
StructField("emp",StringType,true),
StructField("dept",StringType,true),
StructField("sal",IntegerType,false),
StructField("rank",IntegerType,true)
)
)
val e2=sqlContext.createDataFrame(expected,schema)
val actual=ScratchPad.get_data_frame(sqlContext.sparkSession)
assertDataFrameEquals(e2,actual)
}
Run Code Online (Sandbox Code Playgroud)
}
当我右键单击intellij中的类并单击"运行"时工作正常.当我使用"sbt test"运行相同的测试时,它会失败并显示以下内容:
java.security.AccessControlException: access denied
org.apache.derby.security.SystemPermission( "engine",
"usederbyinternals" )
at java.security.AccessControlContext.checkPermission(AccessControlContext.java:472)
at java.security.AccessController.checkPermission(AccessController.java:884)
at org.apache.derby.iapi.security.SecurityUtil.checkDerbyInternalsPrivilege(Unknown Source)
...
Run Code Online (Sandbox Code Playgroud)
这是我的SBT脚本,没什么好看的 - 必须放入hive依赖,否则测试不会编译:
name := "WindowingTest"
version := "0.1"
scalaVersion := "2.11.5"
libraryDependencies += "org.apache.spark" %% "spark-core" % "2.2.1"
libraryDependencies += "org.apache.spark" %% "spark-sql" % "2.2.1"
libraryDependencies += "org.apache.spark" %% "spark-hive" % "2.2.1"
libraryDependencies += "com.holdenkarau" %% "spark-testing-base" % "2.2.0_0.8.0" % "test"
Run Code Online (Sandbox Code Playgroud)
Google搜索将我指向derby-6648(https://db.apache.org/derby/releases/release-10.12.1.1.cgi)
其中说:需要更改应用程序在SecurityManager下运行Derby的用户必须编辑策略文件,并为derby.jar,derbynet.jar和derbyoptionaltools.jar授予以下额外权限:
权限org.apache.derby.security.SystemPermission"engine","usederbyinternals";
由于我没有明确安装derby(内部可能由spark使用),我该怎么做?
遵循快速而肮脏的黑客解决了问题
System.setSecurityManager(null)
Run Code Online (Sandbox Code Playgroud)
无论如何,因为它仅与自动化测试相关,也许它毕竟不是那么有问题;)