addressDictionary已弃用:首先在iOS 11.0中弃用-使用@properties

iOS*_*iOS 5 cocoa-touch google-maps objective-c core-location ios

我正在与您联系以获取位置和地址。因为我成功地找到了位置,但是在获得地址的同时,我得到了警告,

'addressDictionary' is deprecated: first deprecated in iOS 11.0 - Use @properties
Run Code Online (Sandbox Code Playgroud)

有什么解决办法...

在此处输入图片说明

iOS*_*iOS 9

在Swift 5中

//let location: CLLocation = CLLocation(latitude: 16.511131, longitude: 80.658725)//Convert lat & lng in to CLLocation

    let geocoder = CLGeocoder()
    geocoder.reverseGeocodeLocation(location) { (placemarksArray, error) in
        print(placemarksArray!)
        if (error) == nil {
            if placemarksArray!.count > 0 {
                let placemark = placemarksArray?[0]
                let address = "\(placemark?.subThoroughfare ?? ""), \(placemark?.thoroughfare ?? ""), \(placemark?.locality ?? ""), \(placemark?.subLocality ?? ""), \(placemark?.administrativeArea ?? ""), \(placemark?.postalCode ?? ""), \(placemark?.country ?? "")"
                print("\(address)")
            }
        }

    }
Run Code Online (Sandbox Code Playgroud)

结果像:

**print(placemarksArray!) :** [20/19, Road Number 19, 20/19, Road Number 19, Wadala West, Mumbai, 400031, Maharashtra, India @ <+19.01761470,+72.85616440> +/- 100.00m, region CLCircularRegion (identifier:'<+19.01732600,+72.85634600> radius 70.52', center:<+19.01732600,+72.85634600>, radius:70.52m)]

**print("\(address)") :** 20/19, Road Number 19, Mumbai, Wadala West, Maharashtra, 400031, India
Run Code Online (Sandbox Code Playgroud)

在目标C中

if (!(error))
    {
        CLPlacemark *placemark = [placemarks objectAtIndex:0];    
        NSString *address = [NSString stringWithFormat:@"%@, %@, %@, %@, %@, %@",
                             placemark.thoroughfare,
                             placemark.locality,
                             placemark.subLocality, 
                             placemark.administrativeArea, 
                             placemark.postalCode,
                             placemark.country];
        NSLog(@"%@", address);

    }
Run Code Online (Sandbox Code Playgroud)


Jer*_*ews 9

迅速回答-旧方法注释掉:

let street = placemark.thoroughfare! // addressDictionary!["Street"] as? String ?? " "
    let city =  placemark.subAdministrativeArea! // addressDictionary!["City"] as? String ?? " "
    let state = placemark.administrativeArea!//addressDictionary!["State"] as? String ?? " "
    let zip =  placemark.isoCountryCode!// addressDictionary!["ZIP"] as? String ?? " "
    let country = placemark.country! // addressDictionary!["Country"] as? String ?? " "
Run Code Online (Sandbox Code Playgroud)