通过SSLError的异常处理请求

Arp*_*ire 2 python error-handling

这是我检查链接的功能。但是,当链接为假时,它将引发错误。例如,它适用于twitter.com,但不适用于twitt.com。

class Quality_Check:
    def check_broken_link(self,data):
        url= requests.head(data)

        try:
            if url.status_code==200 or url.status_code==302 or url.status_code==301:
                return True
        except requests.exceptions.SSLError as e:
            return False

qc=Quality_Check()
print(qc.check_broken_link('https://twitte.com'))
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当我尝试通过此方法处理异常时,显示以下错误:

Traceback (most recent call last):
      ssl.SSLError: [SSL: CERTIFICATE_VERIFY_FAILED] certificate verify failed (_ssl.c:749)
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在处理上述异常期间,发生了另一个异常:

raise MaxRetryError(_pool, url, error or ResponseError(cause))
urllib3.exceptions.MaxRetryError: HTTPSConnectionPool(host='twitte.com', 
port=443): Max retries exceeded with url: / (Caused by SSLError(SSLError(1, 
'[SSL: CERTIFICATE_VERIFY_FAILED] certificate verify failed (_ssl.c:749)'),))
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还有一个也出现了

requests.exceptions.SSLError: HTTPSConnectionPool(host='twitte.com', port=443): Max retries exceeded with url: / (Caused by SSLError(SSLError(1, '[SSL: CERTIFICATE_VERIFY_FAILED] certificate verify failed (_ssl.c:749)'),))
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Fat*_*ici 5

url= requests.head(data)在线发生异常。因此,您应该try像这样包含该行:

class Quality_Check:
    def check_broken_link(self,data):
        try:
            url = requests.head(data)
            if url.status_code == 200 or url.status_code == 302 or url.status_code == 301:
                return True
        except requests.exceptions.SSLError as e:
            return False

qc=Quality_Check()
qc.check_broken_link('https://twitte.com')
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返回False,然后'https://twitter.com'返回True,这是所需的结果。


顺便说一句,您可以更改

if url.status_code == 200 or url.status_code == 302 or url.status_code == 301:
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if url.status_code in (200, 302, 301):
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