pro*_*eek 9 python xml elementtree
当值小于5时,我需要遍历XML树以添加子元素.例如,可以将此XML修改为
<?xml version="1.0" encoding="UTF-8"?>
<A value="45">
<B value="30">
<C value="10"/>
<C value ="20"/>
</B>
<B value="15">
<C value = "5" />
<C value = "10" />
</B>
</A>
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这个XML.
<?xml version="1.0" encoding="UTF-8"?>
<A value="45">
<B value="30">
<C value="10"/>
<C value ="20"/>
</B>
<B value="15">
<C value = "5"><D name="error"/></C>
<C value = "10" />
</B>
</A>
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我怎么能用Python的ElementTree做到这一点?
sco*_*fey 13
你可能犯了一个拼写错误,因为在这个例子中,一个错误元素被追加为一个元素的子元素,它的值是10,不小于5.但我认为这是个主意:
#!/usr/bin/env python
from xml.etree.ElementTree import fromstring, ElementTree, Element
def validate_node(elem):
for child in elem.getchildren():
validate_node(child)
value = child.attrib.get('value', '')
if not value.isdigit() or int(value) < 5:
child.append(Element('D', {'name': 'error'}))
if __name__ == '__main__':
import sys
xml = sys.stdin.read() # read XML from standard input
root = fromstring(xml) # parse into XML element tree
validate_node(root)
ElementTree(root).write(sys.stdout, encoding='utf-8')
# write resulting XML to standard output
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鉴于此输入:
<?xml version="1.0" encoding="UTF-8"?>
<A value="45">
<B value="30">
<C value="1"/>
<C value="20"/>
</B>
<B value="15">
<C value="5" />
<C value="10" />
<C value="foo" />
</B>
</A>
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这是输出:
<A value="45">
<B value="30">
<C value="1"><D name="error" /></C>
<C value="20" />
</B>
<B value="15">
<C value="5" />
<C value="10" />
<C value="foo"><D name="error" /></C>
</B>
</A>
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