如何仅显示值为0的项目?

Ste*_*pma 6 php database wordpress

我正在为WordPress创建一个插件.使用此插件,管理员可以从后端插入项目.这些项目在数据库中的值始终为"0".

从ui每个人都可以插入一个项目,但这些项目在数据库中获得值"1".

我只想在GUI的页面上显示值为"0"的项目.

使用此代码,我在我的课程中获取数据库项目.

public function getProjectenList() {

    global $wpdb;
    $return_array = array();

    $result_array = $wpdb->get_results("SELECT * FROM `" . $wpdb->prefix . 
      "ivs_canvas_tabel` ORDER BY `id`", ARRAY_A);
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这是视图中的代码:

   <?php
    if ($projecten->getNrOfProjecten() < 1) {
        ?>
        <tr><td colspan="4">Voeg een project of media-uiting toe</tr>
        <?php
    } else {
        $cat_list = $projecten->getProjectenList();

        //** Show all projects in the tabel
        foreach ($cat_list as $project_obj) {
            // Create update link
            $params = array('action' => 'update', 'id' => $project_obj->getId());
            // Add params to base url update link
            $upd_link = add_query_arg($params, $base_url);

            // Create delete link
            $params = array('action' => 'delete', 'id' => $project_obj->getId());
            // Add params to base url delete link
            $del_link = add_query_arg($params, $base_url);
            ?>

            <tr><td width="10" style="vertical-align: top;"><?php echo $project_obj->getId(); ?>
                </td>
                <?php
                // If update and id match show update form
                // Add hidden field id for id transfer
                if (($action == 'update') &&
                        ($project_obj->getId() == $get_array['id'])) {
                    ?> 
                    <td width="150" style="vertical-align: top;"><input type="hidden" name="id" value="<?php echo $project_obj->getId(); ?>">
                        <input type="text" name="naam" value="<?php echo $project_obj->getNaam(); ?>"></td>
                    <td width="10" style="vertical-align: top;"><input type="text" name="level" value ="<?php echo $project_obj->getLevel(); ?>"></td>
                    <td width="300" style="vertical-align: top;"><textarea name="beschrijving" maxlength="200"> <?php echo $project_obj->getBeschrijving(); ?></textarea></td>
                    <td><input type='file' name='afbeelding' value="<?= IVS_CANVAS_PLUGIN_INCLUDES_UPLOAD_IMGS_DIR_URL . $project_obj->getAfbeelding() ?>"></td>


                    <td colspan="2"><input type="submit" name="update" 
          value="Updaten"/></td>
                <?php } else { ?>
                    <td width="150" style="vertical-align: top;"><?php echo 
          $project_obj->getNaam(); ?></td>
                    <td width="10" style="vertical-align: top;"><?php echo 
        $project_obj->getLevel(); ?></td>
                    <td width="300" style="vertical-align: top;"><?php echo $project_obj->getBeschrijving(); ?></td>
                    <td width="100"><img src="<?= IVS_CANVAS_PLUGIN_INCLUDES_UPLOAD_IMGS_DIR_URL . $project_obj->getAfbeelding() ?>" width="100px" height="100px"/></td></td>



                    <?php
                    if ($action !== 'update') {
                        // If action is update don’t show the action button
                        ?>
                        <td><button><a href="<?php echo $upd_link; ?
       >">Wijzigen</a></button></td>
                        <td><button><a href="<?php echo $del_link; ?
       >">Verwijderen</a></button></td>
                        <?php
                    } // if action !== update
                    ?>

                <?php } // if acton !== update  ?>                   


            </tr>
            <?php
        }
    }
    ?>
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表结构

   $sql = "CREATE TABLE $table_name (
        id int (100) NOT NULL AUTO_INCREMENT,
        naam varchar (255) NOT NULL,
        level int (10) NOT NULL,
        beschrijving varchar (1024) NOT NULL,
        afbeelding varchar(1024) NOT NULL,
        status int (1) NOT NULL,
        PRIMARY KEY  (id)
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)

我希望有人可以帮助我!

M K*_*aid 0

如果您只想在某些列中值为 0 的项目,您可以where在查询中添加过滤器

$result_array = $wpdb->get_results("SELECT * FROM `" . $wpdb->prefix . "ivs_canvas_tabel` WHERE some_column = 0 ORDER BY `id`", ARRAY_A);
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上面将仅返回为零的项目,如果管理项目和用户项目具有此标志,some_column则使用您的列名称some_column