Angular 4中的WebSocket

Lai*_*iso 7 websocket observable rxjs typescript angular

我正在使用Angular 4和websocket创建一个聊天应用程序.为此,我遵循了这个Angular websocket教程

这是WebsocketService源代码:

import { Injectable } from '@angular/core';
import * as Rx from 'rxjs/Rx';

@Injectable()
export class WebsocketService {
  constructor() { }

  private subject: Rx.Subject<MessageEvent>;

  public connect(url): Rx.Subject<MessageEvent> {
    if (!this.subject) {
      this.subject = this.create(url);
      console.log("Successfully connected: " + url);
    } 
    return this.subject;
  }

  private create(url): Rx.Subject<MessageEvent> {
    let ws = new WebSocket(url);

    let observable = Rx.Observable.create(
    (obs: Rx.Observer<MessageEvent>) => {
        ws.onmessage = obs.next.bind(obs);
        ws.onerror = obs.error.bind(obs);
        ws.onclose = obs.complete.bind(obs);
        return ws.close.bind(ws);
    })
let observer = {
        next: (data: Object) => {
            if (ws.readyState === WebSocket.OPEN) {
                ws.send(JSON.stringify(data));
            }
        }
    }
    return Rx.Subject.create(observer, observable);
  }

}
Run Code Online (Sandbox Code Playgroud)

这是我的ChatService:

import { Injectable } from '@angular/core';
import { Observable, Subject } from 'rxjs/Rx';
import { WebsocketService } from './websocket.service';

const CHAT_URL = 'ws://echo.websocket.org/';

export interface Message {
    author: string,
    message: string
}

@Injectable()
export class ChatService {
    public messages: Subject<Message>;

    constructor(wsService: WebsocketService) {
        this.messages = <Subject<Message>>wsService
            .connect(CHAT_URL)
            .map((response: MessageEvent): Message => {
                let data = JSON.parse(response.data);
                return {
                    author: data.author,
                    message: data.message
                }
            });
    }
}
Run Code Online (Sandbox Code Playgroud)

它工作正常,但我想检测连接状态.我想知道连接是否已中断或服务器是否已关闭.

为此,我尝试isServerOn()WebsocketService类中实现一个函数,如下所示:

isServerOn(): Observable<boolean> {
    return Observable.of(!!this.subject);
}
Run Code Online (Sandbox Code Playgroud)

但它还没有解决问题.是否有人鼓励同样的问题?

先感谢您.

lui*_*les 5

我建议你在Angular应用程序中使用socket.io-client的类型定义.然后按如下方式定义服务:

import { Injectable } from '@angular/core';
import { Observable } from 'rxjs/Observable';
import { Observer } from 'rxjs/Observer';
import { Message } from '../model/message';
import { Event } from '../model/event';

import * as socketIo from 'socket.io-client';

const SERVER_URL = 'https://yourserverhost.com';

@Injectable()
export class SocketService {
    private socket;

    public initSocket(): void {
        this.socket = socketIo(SERVER_URL);
    }

    public send(message: Message): void {
        this.socket.emit('message', message);
    }

    public onEvent(event: Event): Observable<any> {
        return new Observable<Event>(observer => {
            this.socket.on(event, () => observer.next());
        });
    }
}
Run Code Online (Sandbox Code Playgroud)

定义事件枚举:

export enum Event {
    CONNECT = 'connect',
    DISCONNECT = 'disconnect'
}
Run Code Online (Sandbox Code Playgroud)

然后subscribe从Angular组件到您的服务功能:

export class ChatComponent implements OnInit {
  constructor(private socketService: SocketService) { }

   ngOnInit(): void {
    this.initIoConnection();
  }

  private initIoConnection(): void {
    this.socketService.initSocket();

    this.ioConnection = this.socketService.onMessage()
      .subscribe((message: Message) => {
        this.messages.push(message);
      });


    this.socketService.onEvent(Event.CONNECT)
      .subscribe(() => {
        console.log('Connected to the server');
      });

    this.socketService.onEvent(Event.DISCONNECT)
      .subscribe(() => {
        console.log('Disconnected');
      });
  }
}
Run Code Online (Sandbox Code Playgroud)

找到完整的聊天项目,在这里使用Node.js,WebSockets和Angular:https://github.com/luixaviles/socket-io-typescript-chat


Pat*_*ter 1

我不确定你想实现什么目标

 return Observable.of(!!this.subject);
Run Code Online (Sandbox Code Playgroud)

我不认为它会做你认为的那样。相反,你应该创建自己的BehaviorSubject并返回相应的Observable,例如

isServerOn(): Observable<boolean> {
    return this.myServerOnSubject.asObservable();
}
Run Code Online (Sandbox Code Playgroud)

在相应的在线/离线代码位置,您可以使用以下命令发出下一个值

this.myServerOnSubject.next(true/false);
Run Code Online (Sandbox Code Playgroud)