格式化值之间具有相同间距的C#字符串

Question

我有3个字符串.第一组字符串是:

"1.0536"  
"2.1"  
"2" 

第二个是:

"Round"  
"Square"  
"Hex"

最后是:

"6061-T6"  
"T351"  
"ASF.3.4.5" 

我需要将三个字符串组合在一起,每个字符串之间的间距相同.我不能使用\ t进行Tab键,因为在我组合字符串后,我将它们发送到Access数据库.

当我组合字符串时,它们看起来像:

"1.0536 Round 6061-T6"  
"2.1 Square T351"  
"2 Hex ASF.3.4.5" 

我真的希望它们看起来像这样,每个字符串之间的间距相同:

"1.0536 Round 6061-T6"
"2.1 Square T351"
"2 Hex ASF.3.4.5"

我怎么能用C#做到这一点？

Answer 1

您可以使用高级功能的string.Format:

string.Format("{0,-10}{1,-10}{2}", ...)

你可以通过写作来做同样的事情 str.PadRight(10)

Answer 2

如果您知道每列的最大长度,请执行以下操作:

String result = String.Format("{0} {1} {2}", strCol1.PadRight(10), strCol2.PadRight(9), strCol3.PadRight(9));

Answer 3

为了让生活更轻松，实用方法：

用法

var data = new[] {
    new[] { "ID", "NAME", "DESCRIPTION" },
    new[] { "1", "Frank Foo", "lorem ipsum sic dolor" },
    new[] { "2", "Brandon Bar", "amet forthrightly" },
    new[] { "3", "B. Baz", "Yeehah!" }
};

var tabbedData = EvenColumns(20, data);
var tabbedData2 = string.Join("\n", EvenColumns(20, false, data)); // alternate line separator, alignment

结果

ID                  NAME                DESCRIPTION
1                   Frank Foo           lorem ipsum sic dolor
2                   Brandon Bar         amet forthrightly
3                   B. Baz              Yeehah!

ID                NAME         DESCRIPTION
1           Frank Foolorem ipsum sic dolor
2         Brandon Bar   amet forthrightly
3              B. Baz             Yeehah!

代码

public string EvenColumns(int desiredWidth, IEnumerable<IEnumerable<string>> lists) {
    return string.Join(Environment.NewLine, EvenColumns(desiredWidth, true, lists));
}

public IEnumerable<string> EvenColumns(int desiredWidth, bool rightOrLeft, IEnumerable<IEnumerable<string>> lists) {
    return lists.Select(o => EvenColumns(desiredWidth, rightOrLeft, o.ToArray()));
}

public string EvenColumns(int desiredWidth, bool rightOrLeftAlignment, string[] list, bool fitToItems = false) {
    // right alignment needs "-X" 'width' vs left alignment which is just "X" in the `string.Format` format string
    int columnWidth = (rightOrLeftAlignment ? -1 : 1) *
                        // fit to actual items? this could screw up "evenness" if
                        // one column is longer than the others
                        // and you use this with multiple rows
                        (fitToItems
                            ? Math.Max(desiredWidth, list.Select(o => o.Length).Max())
                            : desiredWidth
                        );

    // make columns for all but the "last" (or first) one
    string format = string.Concat(Enumerable.Range(rightOrLeftAlignment ? 0 : 1, list.Length-1).Select( i => string.Format("{{{0},{1}}}", i, columnWidth) ));

    // then add the "last" one without Alignment
    if(rightOrLeftAlignment) {
        format += "{" + (list.Length-1) + "}";
    }
    else {
        format = "{0}" + format;
    }

    return string.Format(format, list);
}

具体到问题

// for fun, assume multidimensional declaration rather than jagged
var data = new[,] {
    { "1.0536", "2.1", "2" },
    { "Round", "Square", "Hex" },
    { "6061-T6", "T351", "ASF.3.4.5" },
};

var tabbedData = EvenColumns(20, Transpose(ToJaggedArray(data)));

和Transpose：

public T[][] Transpose<T>(T[][] original) {
    // flip dimensions
    var h = original.Length;
    var w = original[0].Length;

    var result = new T[h][];
    for (var r = 0; r < h; r++) {
        result[r] = new T[w];
        for (var c = 0; c < w; c++)
        {
            result[r][c] = original[c][r];
        }
    }
    return result;
}

和多维数组（来源）：

public T[][] ToJaggedArray<T>(T[,] multiArray) {
    // via /sf/ask/210715361/
    var h = multiArray.GetLength(0);
    var w = multiArray.GetLength(1);

    var result = new T[h][];
    for (var r = 0; r < h; r++) {
        result[r] = new T[w];
        for (var c = 0; c < w; c++) {
            result[r][c] = multiArray[r, c];
        }
    }
    return result;
}