how to parse xml with multiple root element

Question

I need to parse both var & group root elements.

Code

import xml.etree.ElementTree as ET
tree_ownCloud = ET.parse('0020-syslog_rules.xml')
root = tree_ownCloud.getroot()

Error

xml.etree.ElementTree.ParseError: junk after document element: line 17, column 0

Sample XML

<var name="BAD_WORDS">core_dumped|failure|error|attack| bad |illegal |denied|refused|unauthorized|fatal|failed|Segmentation Fault|Corrupted</var>

<group name="syslog,errors,">
  <rule id="1001" level="2">
    <match>^Couldn't open /etc/securetty</match>
    <description>File missing. Root access unrestricted.</description>
    <group>pci_dss_10.2.4,gpg13_4.1,</group>
  </rule>

  <rule id="1002" level="2">
    <match>$BAD_WORDS</match>
    <options>alert_by_email</options>
    <description>Unknown problem somewhere in the system.</description>
    <group>gpg13_4.3,</group>
  </rule>
</group>

I tried following couple of other questions on stackoverflow here, but none helped.

我知道原因，由于它没有得到解析，所以人们通常尝试使用hack。IMO这是一个非常常见的用例，它在XML中具有多个根元素，并且ET解析库中必须存在某些元素才能完成此操作。

Answer 1

如注释中所述，XML文件不能具有多个根。就那么简单。

如果您确实以这种格式接收/存储数据（那么它就是不正确的XML）。您可以考虑用假标签包围您的物品，例如

import xml.etree.ElementTree as ET

with open("0020-syslog_rules.xml", "r") as inputFile: 
  fileContent = inputFile.read()
  root = ET.fromstring("<fake>" + fileContent +"</fake>")
  print(root)