Dud*_*985 3 mysql row row-number
我有这样的桌子
+------+----------+------------+
| id | 1_value | 2_value |
+------+----------+------------+
| 3 | foo1 | other |
| 10 | fooX | stuff |
| 13 | fooJ | here |
| 22 | foo7 | and |
| 31 | foou | here |
+------+----------+------------+
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我想要得到的是拥有行号
我试图做这样的事情
SELECT id, @curRow := @curRow + 1 AS row_number
FROM table
JOIN (SELECT @curRow := 0) r
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而且确实有效...
+------+--------------+
| id | row_number |
+------+--------------+
| 3 | 1 |
| 10 | 2 |
| 13 | 3 |
| 22 | 4 |
| 31 | 5 |
+------+--------------+
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但是,如果我尝试选择特定的行怎么办?
SELECT id, @curRow := @curRow + 1 AS row_number
FROM srwk_esp_registration
JOIN (SELECT @curRow := 0) r
WHERE ID = 22
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在这种情况下,row_number为1,但应为4。
我该如何实现?
如果你不想声明一个变量(SET @rownum something)...
通常,我的正常查询是
SELECT t.* FROM ticket t
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我会在@i:=@i+1 as row_number,之前或之后添加t.*并加入表格(SELECT @i:=0):
SELECT @i:=@i+1 as row_number, t.* FROM ticket t, (SELECT @i:=0) AS temp
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尝试更改示例查询并希望它会有所帮助。
祝你好运!
尝试使用子查询:
SELECT *
FROM (
SELECT id,
@curRow := @curRow + 1 AS row_number
FROM srwk_esp_registration
JOIN (
SELECT @curRow := 0
) r
) sub
WHERE sub.ID = 22
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