abd*_*rik 5 mongodb aggregation-framework
我$lookup在我的聚合查询中使用过。但正如我所见,它的工作原理是LEFT OUTER JOIN.
我想使用
$lookup.
有没有办法完成它?
这是我的inventory收藏:
/* 1 */
{
"_id" : 1,
"sku" : "abc",
"description" : "product 1",
"instock" : 120
}
/* 2 */
{
"_id" : 2,
"sku" : "def",
"description" : "product 2",
"instock" : 80
}
/* 3 */
{
"_id" : 3,
"sku" : "ijk",
"description" : "product 3",
"instock" : 60
}
/* 4 */
{
"_id" : 4,
"sku" : "jkl",
"description" : "product 4",
"instock" : 70
}
/* 5 */
{
"_id" : 5,
"sku" : null,
"description" : "Incomplete"
}
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这是我的orders收藏
/* 1 */
{
"_id" : 1,
"item" : "abc",
"price" : 12,
"quantity" : 2
}
/* 2 */
{
"_id" : 2,
"item" : "jkl",
"price" : 20,
"quantity" : 1
}
/* 3 */
{
"_id" : 10,
"item" : "jklw",
"price" : 20,
"quantity" : 1
}
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这是查询
db.getCollection('inventory').aggregate([
{
$lookup:
{
from: "orders",
localField: "sku",
foreignField: "item",
as: "inventory_docs"
}
}
])
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在此查询我得到的所有inventory's文件与相匹配orders的文件
预期结果
/* 1 */
{
"_id" : 1,
"sku" : "abc",
"description" : "product 1",
"instock" : 120,
"inventory_docs" : [
{
"_id" : 1,
"item" : "abc",
"price" : 12,
"quantity" : 2
}
]
}
/* 2 */
{
"_id" : 4,
"sku" : "jkl",
"description" : "product 4",
"instock" : 70,
"inventory_docs" : [
{
"_id" : 2,
"item" : "jkl",
"price" : 20,
"quantity" : 1
}
]
}
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Neo*_*dan 11
只需添加$match跳过带有空inventory_docs字段的文档的管道阶段。没有其他方法可以实现这一目标。
询问:
db.getCollection('inventory').aggregate([
{
$lookup: {
from: "orders",
localField: "sku",
foreignField: "item",
as: "inventory_docs"
}
},
{
$match: {
"inventory_docs": {$ne: []}
}
}
])
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结果:
{
"_id" : 1.0,
"sku" : "abc",
"description" : "product 1",
"instock" : 120.0,
"inventory_docs" : [
{
"_id" : 1.0,
"item" : "abc",
"price" : 12.0,
"quantity" : 2.0
}
]
}
{
"_id" : 4.0,
"sku" : "jkl",
"description" : "product 4",
"instock" : 70.0,
"inventory_docs" : [
{
"_id" : 2.0,
"item" : "jkl",
"price" : 20.0,
"quantity" : 1.0
}
]
}
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