ozm*_*ozm 6 node.js typescript joi
我正在使用带有TypeScript的joi和@ types/joi.Joi有一个extend方法,它允许通过返回一个新实例来扩展joi,而无需修改原始的joi库.我用它创建了一个扩展实例.
为了这个扩展实例创建的定义,我试图Module Augmentation
描述这里使用下面的代码:
declare module 'joi' {
// Add a new Schema type which has noChildren() method.
interface CustomSchema extends ObjectSchema {
noChildren(): this;
}
}
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但是,正如预期的那样,这会通过扩充来修改原始定义.我想要的是为扩展实例创建定义,它继承原始内容而不修改它.
还扩展Joi
了如下:
import * as Joi from 'joi';
const JoiExtended = Joi.extend({...some implementation...})
// How to export?
// export * from 'Joi' ---> In this case, original non-extended Joi is exported
// export default JoiExtended ---> Imported `Joi` reports: Cannot find namespace 'Joi'
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Joi
?PS我正在学习TypeScript并寻找这个问题的答案但是找不到答案,也许,因为我不习惯使用打字稿术语并搜索错误的术语.
Joi.extend
返回joi
可以使用导出Root
类型的模块的新实例.
您需要创建一个扩展的接口,Joi.Root
另一个扩展joi
您正在扩展的基本类型.您可以joi
像导入任何其他对象一样导出自定义实例.
下面是使用API文档示例中的round()
和dividable()
规则的示例.extend()
import * as Joi from 'joi';
interface ExtendedNumberSchema extends Joi.NumberSchema {
round(): this;
dividable(num: number): this;
}
interface ExtendedJoi extends Joi.Root {
number(): ExtendedNumberSchema;
}
const customJoi: ExtendedJoi = Joi.extend((joi) => ({
base: joi.number(),
name: 'number',
language: {
round: 'needs to be a rounded number', // Used below as 'number.round'
dividable: 'needs to be dividable by {{q}}'
},
pre(value, state, options) {
if (options.convert && this._flags.round) {
return Math.round(value); // Change the value
}
return value; // Keep the value as it was
},
rules: [
{
name: 'round',
setup(params) {
this._flags.round = true; // Set a flag for later use
},
validate(params, value, state, options) {
if (value % 1 !== 0) {
// Generate an error, state and options need to be passed
return this.createError('number.round', {v: value}, state, options);
}
return value; // Everything is OK
}
},
{
name: 'dividable',
params: {
q: joi.alternatives([joi.number().required(), joi.func().ref()])
},
validate(params, value, state, options) {
if (value % params.q !== 0) {
// Generate an error, state and options need to be passed, q is used in the language
return this.createError('number.dividable', {v: value, q: params.q}, state, options);
}
return value; // Everything is OK
}
}
]
}));
const schema = {
a: customJoi.number().round().dividable(3)
};
const result = customJoi.validate({a: 4.1}, schema); // will fail because 4 is no divisible by 3
console.log(result);
export = customJoi;
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