zs_*_*ily 5 python sql-server sqlalchemy
我在SQLAlchemy中找不到此简单查询的解决方案示例。SQLAlchemy可以替换T-SQL ETL数据吗?
select a.field1, a.field2, b.field2
from database1.schema1.table_a as a
inner join database2.schema1.table_b as b
on a.fileld1 = b.fileld1
Run Code Online (Sandbox Code Playgroud)
我将此连接用于Windows身份验证:
engine = create_engine(
"mssql+pyodbc://@{Server}/{database}?driver=SQL+Server?trusted_connection=yes"
)
Run Code Online (Sandbox Code Playgroud)
您需要的是多部分模式名称。如果您使用__table_args__声明性 \xe2\x80\x93,则使用 \xe2\x80\x93 将允许您执行查询。由于您省略了表或模型定义,我将根据您的查询示例生成示例:
In [8]: class TableA(Base):\n ...: __tablename__ = \'table_a\'\n ...: __table_args__ = {\n ...: \'schema\': \'database1.schema1\'\n ...: }\n ...: id = Column(Integer, primary_key=True)\n ...: field1 = Column(Integer)\n ...: field2 = Column(Integer)\n ...: \n\nIn [9]: class TableB(Base):\n ...: __tablename__ = \'table_b\'\n ...: __table_args__ = {\n ...: \'schema\': \'database2.schema1\'\n ...: }\n ...: id = Column(Integer, primary_key=True)\n ...: field1 = Column(Integer)\n ...: field2 = Column(Integer)\n ...: \n\nIn [10]: q = session.query(TableA.field1, TableA.field2, TableB.field2).\\\n ...: join(TableB, TableA.field1 == TableB.field1)\n\nIn [12]: q.statement.compile(dialect=mssql.dialect())\nOut[12]: <sqlalchemy.dialects.mssql.base.MSSQLCompiler at 0x7fa3886027b8>\n\nIn [13]: print(_)\nSELECT database1.schema1.table_a.field1, database1.schema1.table_a.field2, database2.schema1.table_b.field2 \nFROM database1.schema1.table_a JOIN database2.schema1.table_b ON database1.schema1.table_a.field1 = database2.schema1.table_b.field1\nRun Code Online (Sandbox Code Playgroud)\n