Pet*_*ack 1 arrays postgresql plpgsql
我正在尝试从共享相同 family_id 的所有狗构建一个声明的数组,并使用该数组查询 dog_characteristics 表。
CREATE OR REPLACE FUNCTION update_dog_characteristics_guarantor_id()
RETURNS trigger AS $$
DECLARE dog_ids INT[];
BEGIN
SELECT id into dog_ids FROM dogs WHERE dogs.family_id = OLD.id;
IF ((OLD.family_id IS NOT NULL) && ((SELECT COUNT(*) FROM dog_ids) > 0)) THEN
UPDATE
dog_characteristics
SET
guarantor_id = NEW.guarantor_id
WHERE
dog_characteristics.account_id = OLD.account_id
AND dog_characteristics.dog_id IN ANY(dog_ids);
RETURN NULL;
END IF;
RETURN NULL;
END;
$$ LANGUAGE plpgsql;
Run Code Online (Sandbox Code Playgroud)
我试过的
AND dog_characteristics.dog_id = ANY(dog_ids);
AND dog_characteristics.dog_id = ANY(dog_ids::int[]);
AND dog_characteristics.dog_id IN (dog_ids::int[]);
AND dog_characteristics.dog_id IN (dog_ids);
AND dog_characteristics.dog_id IN (ARRAY(dog_ids));
AND dog_characteristics.dog_id IN ARRAY(dog_ids);
AND dog_characteristics.dog_id IN implode( ',', dog_ids);
Run Code Online (Sandbox Code Playgroud)
最常见的错误
ERROR: malformed array literal: "672"
DETAIL: Array value must start with "{" or dimension information.
CONTEXT: PL/pgSQL function update_dog_characteristics_guarantor_id() line 5 at SQL statement
Run Code Online (Sandbox Code Playgroud)
您的触发器函数中有多个错误。
正如dog_ids声明为数组一样,第一个选择的结果也必须是一个数组。为此,您需要聚合从查询返回的所有 ID。
所以第一个选择语句应该是
select array_agg(id) --<< aggregate all IDs into an array
into dog_ids
FROM dogs
WHERE dogs.family_id = OLD.id;
Run Code Online (Sandbox Code Playgroud)
要检查数组是否有元素,您不能使用select count(*),您需要使用array_length()或cardinality()。
该&&不是“AND”运算符的SQL -这就是AND-所以if应该是:
IF OLD.family_id IS NOT NULL AND cardinality(dog_ids) > 0 THEN
...
END IF;
Run Code Online (Sandbox Code Playgroud)
数组上的 where 条件应该是:
AND dog_characteristics.dog_id = ANY(dog_ids);
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
4025 次 |
| 最近记录: |