如何捕获RxJS 5.5中的错误

der*_*zay 3 rxjs rxjs5 angular

Angular 5和RXJS 5.5一起使用

在我做这样的事情之前

getProjectInfo(id): Observable<any> {
    const URL = `${this.API}/${id}`;
    return this.http.get(URL)
      .pipe(map(res => res)),
      catchError(this.handleServerError);
}

handleServerError(error: any) {
    console.log(error.error || error.json() || error);
    return Observable.throw(error.error || error.json() || error || 'Server error');
}
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但现在我收到了这个错误

Error:(21, 5) TS2322:Type 'UnaryFunction<Observable<{}>, Observable<any>>' is not assignable to type 'Observable<any>'.
  Property '_isScalar' is missing in type 'UnaryFunction<Observable<{}>, Observable<any>>'.
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我也试过这个

getProjectInfo(id): Observable<any> {
    const URL = `${this.API}/${id}`;
    return this.http.get(URL)
      .pipe(map(res => res)),
      catchError(err => this.handleError('getProjInfo', URL));
}
private handleError(method: String, URL: string): any {
  return (err: any) => {
    const errMsg = `error in ${method}() retrieving ${URL}`;
    console.log(`${errMsg}:`, err);
    if (err instanceof HttpErrorResponse) {
      console.log(`status: ${err.status}, ${err.statusText}`);
    }
    return Observable.throw(errMsg);
  };
}
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我究竟做错了什么?

Dan*_*nko 13

请记住您的括号.您返回pipe结果和catchEror结果除以,:

return this.http.get(URL)
  .pipe(map(res => res)),
  catchError(this.handleServerError);
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将一个支架放在自己的位置:

return this.http.get(URL)
  .pipe(
    map(res => res),
    catchError(this.handleServerError)
  );
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