如何对嵌套关系进行分页？

Question

我读了django-rest-framework 嵌套关系：

你可以tracks看到AlbumSerializer：

class TrackSerializer(serializers.ModelSerializer):
    class Meta:
        model = Track
        fields = ('order', 'title', 'duration')

class AlbumSerializer(serializers.ModelSerializer):
    tracks = TrackSerializer(many=True, read_only=True)

    class Meta:
        model = Album
        fields = ('album_name', 'artist', 'tracks')

官网没有给出分页的方法tracks，AlbumSerializer如果曲目数太多，如何实现曲目分页呢？

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编辑

我想通过将页码传递给 API 来对其进行分页。

Answer 1

Django 有一些分页器类可以帮助您自己构建它。

如果你想建立一个分页，你可以这样做：

from django.core.paginator import Paginator

def viewPage(request, page):
    paginator = Paginator(data, 10) # 10 being how many objects per page you want, data being an array of tracks
    try:
        tracks = paginator.page(page)
    except PageNotAnInteger:
        # If page is not an integer, deliver first page.
        tracks = paginator.page(1)
    except EmptyPage:
        # If page is out of range (e.g. 9999), deliver last page of results.
        tracks = paginator.page(paginator.num_pages)    
    return render(request, 'view_page.html', {
        'tracks': tracks,
    })

您需要提供给 Paginator() 的数据是作为可迭代对象的整个曲目集合。