Sal*_*500 11 android firebase-job-dispatcher
作为From Firebase JobDispatcher文档Firebase JobDispatcher
setTrigger(Trigger.executionWindow(0, 60))
// start between 0 and 60 seconds
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但为什么我的服务运行两次
Firebase JobDispacther代码
FirebaseJobDispatcher dispatcher = new FirebaseJobDispatcher(new GooglePlayDriver(this));
Job job = dispatcher.newJobBuilder()
.setTag("testing job")
.setService(TestingJob.class)
.setReplaceCurrent(true)
.setRecurring(true)
.setTrigger(Trigger.executionWindow(0,1))
.setConstraints(Constraint.ON_ANY_NETWORK)
.setLifetime(Lifetime.FOREVER)
.build();
dispatcher.mustSchedule(job);
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测试类(工作服务)
public class TestingJob extends JobService {
private static final String TAG = "TestingJob";
private int i =0;
@Override
public boolean onStartJob(JobParameters job) {
Log.d(TAG, "onStartJob Testing Job: "+new Date().toString());
Log.d(TAG, "onStartJob: i = "+String.valueOf(i));
i+=1;
return false;
}
@Override
public boolean onStopJob(JobParameters job) {
Log.d(TAG, "onStopJob Testing Job: Stopped");
return false;
}
}
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记录猫
11-28 00:08:57.666 11793-11793: onStartJob Testing Job: Tue Nov 28 00:08:57 GMT+05:00 2017
11-28 00:08:57.666 11793-11793: onStartJob: i = 0
11-28 00:08:57.791 11793-11793: onStartJob Testing Job: Tue Nov 28 00:08:57 GMT+05:00 2017
11-28 00:08:57.791 11793-11793: onStartJob: i = 0
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表现
<uses-permission android:name="android.permission.RECEIVE_BOOT_COMPLETED" />
<service android:name=".services.TestingJob"
android:exported="false">
<intent-filter>
<action android:name="com.firebase.jobdispatcher.ACTION_EXECUTE"/>
</intent-filter>
</service>
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我可以使用我的工作服务再次意味着int i每次都应该增加.
Thnx为您提供帮助
我认为我们应该了解一些方法
FirebaseJobDispatcher dispatcher = new FirebaseJobDispatcher(new GooglePlayDriver(this));
Job job = dispatcher.newJobBuilder()
.setTag("testing job")
.setService(TestingJob.class)
.setReplaceCurrent(true)
.setRecurring(true)
.setTrigger(Trigger.executionWindow(0,1))
.setConstraints(Constraint.ON_ANY_NETWORK)
.setLifetime(Lifetime.FOREVER)
.build();
dispatcher.mustSchedule(job);
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您在此设置
.setRecurring(true):这意味着不断重复。设置触发器的 start 和 end
.setTrigger(Trigger.executionWindow(start, end)):
.setReplaceCurrent(false):这意味着不要使用相同标签覆盖现有作业。
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