Ank*_*oni 3 mongodb mongodb-query
我是MongoDB 3.2 的新手,
考虑下面的例子,
{ "_id" : "2tLX8ALYfRvbgiurZ", "service" : "GSTR 1" }
{ "_id" : "2tLX8ALYfRvbgiurZ", "service" : "GSTR 2" }
{ "_id" : "2tLX8ALYfRvbgiurZ", "service" : "GSTR 3" }
Run Code Online (Sandbox Code Playgroud)
如何使用Group By _id并创建单个字段并连接所有文档字段,以下是预期的输出,
{ "_id" : "2tLX8ALYfRvbgiurZ", "service" : "GSTR 1, GSTR 2, GSTR 3" }
Run Code Online (Sandbox Code Playgroud)
我在下面使用但它给出了数组,
db.getCollection('Clients').aggregate(
[
{
$group : {
_id : "$_id",
services : "$services"
}
}
]
).map( doc =>
Object.assign(
doc,
{ "services": doc.services.join(",") }
)
);
Run Code Online (Sandbox Code Playgroud)
它给出输出为
[{ "_id" : "2tLX8ALYfRvbgiurZ", "service" : "GSTR 1, GSTR 2, GSTR 3" }]
Run Code Online (Sandbox Code Playgroud)
小智 5
我检查过它工作正常
db.client.insert([
{ "id" : "2tLX8ALYfRvbgiurZ", "service" : "GSTR 1" },
{ "id" : "2tLX8ALYfRvbgiurZ", "service" : "GSTR 2" },
{ "id" : "2tLX8ALYfRvbgiurZ", "service" : "GSTR 3" }
]);
Run Code Online (Sandbox Code Playgroud)
db.client.insert([
{ "id" : "2tLX8ALYfRvbgiurZ", "service" : "GSTR 1" },
{ "id" : "2tLX8ALYfRvbgiurZ", "service" : "GSTR 2" },
{ "id" : "2tLX8ALYfRvbgiurZ", "service" : "GSTR 3" }
]);
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
1536 次 |
| 最近记录: |