使用TypeScript将导入导出为命名空间

Question

我的问题与此问题几乎相同:https: //github.com/Microsoft/TypeScript/issues/4529

说我有这个:

//exported imports
export {ISumanOpts, IGlobalSumanObj} from 'suman-types/dts/global';
export {ITestCaseParam} from 'suman-types/dts/test-suite';
export {IHookParam} from 'suman-types/dts/test-suite';
export {IDescribeFn} from 'suman-types/dts/describe';
export {ItFn, ITestDataObj} from 'suman-types/dts/it';
export {IBeforeFn} from 'suman-types/dts/before';
export {IBeforeEachFn} from 'suman-types/dts/before-each';
export {IAfterFn} from 'suman-types/dts/after';
export {IAfterEachFn} from 'suman-types/dts/after-each';
export {DefineObjectContext as IDefObjCtx} from "./test-suite-helpers/define-options-classes";
export {DefineObjectTestCase as IDefObjTestCase} from "./test-suite-helpers/define-options-classes";
export {DefineObjectAllHook as IDefObjAllHook} from "./test-suite-helpers/define-options-classes";
export {DefineObjectEachHook as IDefObjEachHook} from "./test-suite-helpers/define-options-classes";


export namespace s {

  // ! I want to move all of the above exported items into a namespace here

}

有没有办法使用namespace或module导出作为命名空间的一部分而不是单独导出它们？

我有这个越来越近了:

所以我尝试将它们更改为导入,然后将它们放在const上,如下所示:

但是正如你所看到的,我的一些声明是接口,而不是类,在这种情况下看起来我得到错误消息"只引用一个类型,但在这里被用作值".

Answer 1

s.ts例如,创建一个文件名,您要在其中导出命名空间的所有内容:

export {ISumanOpts, IGlobalSumanObj} from 'suman-types/dts/global';
export {ITestCaseParam} from 'suman-types/dts/test-suite';
export {IHookParam} from 'suman-types/dts/test-suite';
export {IDescribeFn} from 'suman-types/dts/describe';
export {ItFn, ITestDataObj} from 'suman-types/dts/it';
export {IBeforeFn} from 'suman-types/dts/before';
export {IBeforeEachFn} from 'suman-types/dts/before-each';
export {IAfterFn} from 'suman-types/dts/after';
export {IAfterEachFn} from 'suman-types/dts/after-each';
export {DefineObjectContext as IDefObjCtx} from "./test-suite-helpers/define-options-classes";
export {DefineObjectTestCase as IDefObjTestCase} from "./test-suite-helpers/define-options-classes";
export {DefineObjectAllHook as IDefObjAllHook} from "./test-suite-helpers/define-options-classes";
export {DefineObjectEachHook as IDefObjEachHook} from "./test-suite-helpers/define-options-classes";

然后在你的模块中你可以做到:

import * as s from './s'

export {s}

它将在名为的命名空间中导出类型和值s.然后可以使用以下方法导入它们

import {s} from 'your-module'

const anObject: s.ISumanOpts = {...}

Answer 2

我所做的是这样的：

import * as Block from './block'
import * as FullNode from './full-node'
import * as ListOnChain from './list-on-chain'
import * as HashTools from './hash-tools'
import * as KeyValueStorage from './key-value-storage'
import * as SequenceStorage from './sequence-storage'
import * as SmartContract from './smart-contract'
import * as NodeBrowser from './node-browser'
import * as NetworkApi from './network-api'
import * as NetworkClientBrowserImpl from './network-client-browser-impl'
import * as NodeApi from './node-api'
import * as NodeImpl from './node-impl'
import * as NodeTransfer from './node-transfer'
import * as NodeNetworkClient from './node-network-client'
import * as WebsocketConnector from './websocket-connector'

export {
    Block,
    FullNode,
    ListOnChain,
    HashTools,
    KeyValueStorage,
    SequenceStorage,
    SmartContract,
    NodeBrowser,
    NetworkApi,
    NetworkClientBrowserImpl,
    NodeApi,
    NodeImpl,
    NodeTransfer,
    NodeNetworkClient,
    WebsocketConnector
}

然后在另一个文件中，我可以像这样导入，并且所有文件都将保留在自己的空间中：

import * as AllComponents from 'blockchain-js-core'

如果你想将它们一一导入，你可以这样做：

import {
    Block,
    FullNode,
    ListOnChain,
    HashTools,
    KeyValueStorage,
    SequenceStorage,
    SmartContract,
    NodeBrowser,
    NetworkApi,
    NetworkClientBrowserImpl,
    NodeApi,
    NodeImpl,
    NodeTransfer,
    NodeNetworkClient,
    WebsocketConnector
} from 'blockchain-js-core'

可以在这里找到一个示例： https: //github.com/ltearno/blockchain-js/blob/master/blockchain-js-core/src/index.ts