MYSQL，WHERE / LIMIT / ORDERBY的组合

Question

我有这个

$sql = 'SELECT * FROM tb_event WHERE DATE(edate) >= DATE(NOW())';
   $result = $conn->query($sql) or die(mysqli_error());
   $news = $result->fetch_assoc();

运行正常但是当我将其更改为此

$sql = 'SELECT * FROM tb_event WHERE DATE(edate) >= DATE(NOW() LIMIT 2)';

我收到此错误消息

Warning: mysqli_error() expects exactly 1 parameter, 0 given in /var/www/.../...php

最后，我想将其与订单结合起来，就像这样

$sql = 'SELECT * FROM tb_event WHERE DATE(edate) >= DATE(NOW() LIMIT 2 ORDER BY DESC)';

我究竟做错了什么？

Answer 1

您需要从 DATE() 宏中取出 limit 子句。

SELECT * FROM tb_event WHERE DATE(edate) >= DATE(NOW()) LIMIT 2

此外，如果您想订购，则必须设置一个字段，例如

SELECT * FROM tb_event WHERE DATE(edate) >= DATE(NOW()) LIMIT 2 ORDER BY myField DESC