Fra*_*ira 4 java arrays lambda hashmap java-8
我想将NxN数组映射到Java 8中的Map.
这个想法是每个[i] [0]元素都是一个键,每个[i] [j] j> 0都是映射中每个键的值列表.
谢谢你的帮助.:)
这是我的班级:
public class GroupingDishes {
public static void main(String[] args) {
String[][] dishes = {
{"Salad", "Tomato", "Cucumber", "Salad", "Sauce"},
{"Pizza", "Tomato", "Sausage", "Sauce", "Dough"},
{"Quesadilla", "Chicken", "Cheese", "Sauce"},
{"Sandwich", "Salad", "Bread", "Tomato", "Cheese"}
};
Map<String, HashSet<String>> groupDishes = groupingDishes(dishes);
}
public static Map<String, HashSet<String>> groupingDishes(String[][] dishes) {
Map<String, HashSet<String>> mapFood = new HashMap<>();
for (int i = 0; i < dishes.length; i++) {
String food = dishes[i][0];
for (int j = 0; j < dishes[i].length; j++) {
if (mapFood.containsKey(food)) {
HashSet<String> existingIngredients = mapFood.get(dishes[i][0]);
existingIngredients.add(dishes[i][j]);
mapFood.put(food, existingIngredients);
} else {
HashSet<String> newIngredient = new HashSet<>();
mapFood.put(food, newIngredient);
}
}
}
return mapFood;
}
}
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您可以使用第一项作为键转换String[][]为流String[],然后收集到地图,String[]其余作为集合的值.
public static Map<String, HashSet<String>> groupingDishes2(String[][] dishes) {
return Arrays.stream(dishes)
.collect(Collectors.toMap(
arr -> arr[0],
arr -> Arrays.stream(arr).skip(1).collect(Collectors.toCollection(HashSet::new))));
}
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顺便说一句,我怀疑你真的需要一个Map<String, HashSet<String>>.将类型更改为更好Map<String, Set<String>>,然后实现也可以更简单.
public static Map<String, Set<String>> groupingDishes(String[][] dishes) {
return Arrays.stream(dishes)
.collect(Collectors.toMap(
arr -> arr[0],
arr -> Arrays.stream(arr).skip(1).collect(Collectors.toSet())));
}
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或者甚至更好,正如@Holger建议的那样,一个更好的选择,因为"带有skip和limit不能很好地执行的流,也Collectors没有得到任何结果的初始容量提示":
public static Map<String, Set<String>> groupingDishes(String[][] dishes) {
return Arrays.stream(dishes)
.collect(Collectors.toMap(
arr -> arr[0],
arr -> new HashSet<>(Arrays.asList(arr).subList(1, arr.length))));
}
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