没有在Linux下的C++中安装的共享对象和包含

Question

我正在编写一个程序,它有两个我需要使用的库:v8和v8-juice.不幸的是,v8-juice无法编译为静态库,因为它与模板有关.还有一些其他的怪癖需要将v8编译为共享对象.

因此,当我编译我的程序时,我最终得到了两个可执行文件运行所需的共享对象.我的问题是,有没有一种方法可以包含这些共享对象而无需在linux下安装它们？对不起,如果这是一个新问题,我对C++很新.

Answer 1

共享库可以与可执行文件位于同一文件夹中.男子ld.so:

   $ORIGIN and rpath

   ld.so  understands the string $ORIGIN (or equivalently ${ORIGIN}) in an
   rpath specification (DT_RPATH or DT_RUNPATH) to mean the directory con-
   taining  the  application  executable.  Thus, an application located in
   somedir/app could be compiled with gcc  -Wl,-rpath,'$ORIGIN/../lib'  so
   that  it  finds  an  associated shared library in somedir/lib no matter
   where somedir is located in the directory hierarchy.  This  facilitates
   the  creation  of  "turn-key"  applications  that  do  not  need  to be
   installed into special directories, but can instead  be  unpacked  into
   any directory and still find their own shared libraries.