如何将`logging`警告变成错误？

Question

我使用的库通过logging模块（logging.Logger'swarn()和error()方法）发出警告和错误。我想实现一个将警告转换为错误的选项（即，警告失败）。

有没有简单的方法来实现这一目标？

通过查看文档，我看不到现成的解决方案。我认为通过添加自定义Handler对象是可能的，但我不确定如何“正确”做到这一点。任何指针？

Answer 1

@hoefling's answer is close, but I would change it like so:

class LevelRaiser(logging.Filter):
    def filter(self, record):
        if record.levelno == logging.WARNING:
            record.levelno = logging.ERROR
            record.levelname = logging.getLevelName(logging.ERROR)
        return True

def configure_library_logging():
    library_root_logger = logging.getLogger(library.__name__)
    library_root_logger.addFilter(LevelRaiser())

The reason is that filters are used to change LogRecord attributes and filter stuff out, whereas handlers are used to do I/O. What you're trying to do here isn't I/O, and so doesn't really belong in a handler.