Est*_*sti 1 loops nested clojure
我是Clojure的新手,我有一个关于嵌套doseq循环的问题.
我想迭代一个序列并得到一个子序列,然后得到一些键来在所有序列元素上应用一个函数.
给定的序列具有或多或少的结构,但有数百本书籍,书架和许多库:
([:state/libraries {6 #:library {:name "MUNICIPAL LIBRARY OF X" :id 6
:shelves {3 #:shelf {:name "GREEN SHELF" :id 3 :books
{45 #:book {:id 45 :name "NECRONOMICON" :pages {...},
{89 #:book {:id 89 :name "HOLY BIBLE" :pages {...}}}}}}}}])
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这是我的代码:
(defn my-function [] (let [conn (d/connect (-> my-system :config :datomic-uri))]
(doseq [library-seq (read-string (slurp "given-sequence.edn"))]
(doseq [shelves-seq (val library-seq)]
(library/create-shelf conn {:id (:shelf/id (val shelves-seq))
:name (:shelf/name (val shelves-seq))})
(doseq [books-seq (:shelf/books (val shelves-seq))]
(library/create-book conn (:shelf/id (val shelves-seq)) {:id (:book/id (val books-seq))
:name (:book/name (val books-seq))})
)))))
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问题是我想摆脱嵌套剂量混乱,但我不知道什么是最好的方法,因为在每次迭代中键都会改变.使用复发?降低?也许我正在以完全错误的方式思考这个问题?
就像Carcigenicate在评论中所说的那样,假设库/ ...函数只是副作用,你可以把它写成一个doseq.
(defn my-function []
(let [conn (d/connect (-> my-system :config :datomic-uri))]
(doseq [library-seq (read-string (slurp "given-sequence.edn"))
shelves-seq (val library-seq)
:let [_ (library/create-shelf conn
{:id (:shelf/id (val shelves-seq))
:name (:shelf/name (val shelves-seq))})]
books-seq (:shelf/books (val shelves-seq))]
(library/create-book conn
(:shelf/id (val shelves-seq))
{:id (:book/id (val books-seq))
:name (:book/name (val books-seq))}))))
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我会将"连接数据库"从"啜饮文件"与"写入数据库"分开.再加上一些解构,我最终会得到一些更像:
(defn write-to-the-db [conn given-sequence]
(doseq [library-seq given-sequence
shelves-seq (val library-seq)
:let [{shelf-id :shelf/id,
shelf-name :shelf/name
books :shelf/books} (val shelves-seq)
_ (library/create-shelf conn {:id shelf-id, :name shelf-name})]
{book-id :book/id, book-name :book/name} books]
(library/create-book conn shelf-id {:id book-id, :name book-name})))
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