Sup*_*rio 0 python sql excel google-sheets pandas
我正在寻找使用python\excel\sql\google表格的最佳方法 - 我需要找到所有符合n值列表中k值的行.
例如,我有一个名为Animals的表:
| Name | mammal | move | dive |
+----------+--------+--------+-------+
| Giraffe | 1 | 1 | 0 |
| Frog | 0 | 1 | 1 |
| Dolphin | 1 | 1 | 1 |
| Snail | 0 | 1 | 0 |
| Bacteria | 0 | 0 | 0 |
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我想编写一个函数foo,其行为如下:
foo(布尔值的元组,最小匹配)
foo((1,1,1),3) -> Dolphin
foo((1,1,1),2) -> Giraffe, Dolphin, Frog
foo((1,1,1),1) -> Giraffe, Dolphin, Frog, Snail
foo((1,1,0),2) -> Giraffe, Dolphin
foo((0,1,1),2) -> Dolphin, Frog
foo((0,1,1),1) -> Giraffe, Dolphin, Frog, Snail
foo((1,1,1),0) -> Giraffe, Dolphin, Frog, Snail, Bacteria
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你最好的想法是什么?
这是一个纯Python 3解决方案.
data = [
('Giraffe', 1, 1, 0),
('Frog', 0, 1, 1),
('Dolphin', 1, 1, 1),
('Snail', 0, 1, 0),
('Bacteria', 0, 0, 0),
]
probes = [
((1, 1, 1), 3),
((1, 1, 1), 2),
((1, 1, 1), 1),
((1, 1, 0), 2),
((0, 1, 1), 2),
((0, 1, 1), 1),
((1, 1, 1), 0),
]
def foo(mask, minmatch):
for name, *row in data:
if sum(u & v for u, v in zip(mask, row)) >= minmatch:
yield name
for mask, minmatch in probes:
print(mask, minmatch, *foo(mask, minmatch))
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产量
(1, 1, 1) 3 Dolphin
(1, 1, 1) 2 Giraffe Frog Dolphin
(1, 1, 1) 1 Giraffe Frog Dolphin Snail
(1, 1, 0) 2 Giraffe Dolphin
(0, 1, 1) 2 Frog Dolphin
(0, 1, 1) 1 Giraffe Frog Dolphin Snail
(1, 1, 1) 0 Giraffe Frog Dolphin Snail Bacteria
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在Python 3.6.0上测试.它使用了旧版本中不可用的一些语法,但很容易使其适应使用较旧的语法.
此变体在旧版本的Python上运行.在Python 2.6.6上测试过.
from __future__ import print_function
data = [
('Giraffe', 1, 1, 0),
('Frog', 0, 1, 1),
('Dolphin', 1, 1, 1),
('Snail', 0, 1, 0),
('Bacteria', 0, 0, 0),
]
probes = [
((1, 1, 1), 3),
((1, 1, 1), 2),
((1, 1, 1), 1),
((1, 1, 0), 2),
((0, 1, 1), 2),
((0, 1, 1), 1),
((1, 1, 1), 0),
]
def foo(mask, minmatch):
for row in data:
if sum(u & v for u, v in zip(mask, row[1:])) >= minmatch:
yield row[0]
for mask, minmatch in probes:
matches = list(foo(mask, minmatch))
print(mask, minmatch, matches)
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产量
(1, 1, 1) 3 ['Dolphin']
(1, 1, 1) 2 ['Giraffe', 'Frog', 'Dolphin']
(1, 1, 1) 1 ['Giraffe', 'Frog', 'Dolphin', 'Snail']
(1, 1, 0) 2 ['Giraffe', 'Dolphin']
(0, 1, 1) 2 ['Frog', 'Dolphin']
(0, 1, 1) 1 ['Giraffe', 'Frog', 'Dolphin', 'Snail']
(1, 1, 1) 0 ['Giraffe', 'Frog', 'Dolphin', 'Snail', 'Bacteria']
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