原始SQL到laravel查询

Question

任何人都可以帮我写下面的SQL语句的数据库查询版本.我需要一些关于select语句和分区连接的帮助.

到目前为止,我已设法做到这一点.

$query = DB::table(raw('SapakInAdminOrder a'))
->select(raw('a.*'))
->leftJoin(raw('currency cu'), 'a.currency', '=', 'cu.id')
->leftJoin(raw('moodboards m'), 'a.orderMoodboardID', '=', 'm.id')
 ->join(raw('clients b'), 'a.clientID', '=', 'b.id')
 ->leftJoin(raw('moodboards mc'), 'b.moodboardID', 'mc.id')
 ->join(raw('sapakim c'), 'b.sapakID', '=', 'c.id')
 ->leftJoin(raw('sapakim sm'), 'c.managerid', '=', 'sm.id')
 ->leftJoin(raw('products p'), 'a.productKey', '=', 'p.id')
 ->where(function ($query) {
     $query->whereNull('a.isDeleted');
     $query->orWhere('a.isDeleted', '!=', 1);
 });

但我需要实现这一目标.

select * from (select ROW_NUMBER() OVER(ORDER BY case when (indesign.status=4 or indesign.statusdate is null) then getdate()+2 else indesign.statusdate end ASC) AS RowNum,a.*
FROM sapakInAdminOrder a 
left join currency cu on cu.id=a.currency
left join moodboards m on m.id=a.orderMoodboardID 
inner join Clients b on a.clientID=b.id 
left join moodboards mc on mc.id=b.moodboardID 
inner join Sapakim c on b.sapakID=c.id 
left join Sapakim sm on sm.id=c.managerid  
left join products p on p.id=a.productKey 
left join (select * from (select ROW_NUMBER() over(PARTITION BY orderID ORDER BY id DESC) r, * from orderCommunication ) f where r=1) chat on chat.orderId = a.id
left join (select id,[status],orderid,approveSMSDate,coverImage,statusDate from (SELECT  id,[status],statusDate,approveSMSDate,coverImage,orderid,ROW_NUMBER() OVER(PARTITION BY orderid ORDER BY id DESC) AS r  FROM  SapakimInAdminDesigns) f where  r=1) indesign on a.id=indesign.orderid
where (a.isDeleted is null or a.isDeleted != 1) and 
      c.inAdminManagerID=(select id from sapakim where sapakguid='test')  and 
      c.sapakguid='test' and 
      a.isFreeDesign=0 and 
      a.transactionID = -1 and 
      (a.designerPaid is null or a.designerPaid=0) and 
      (chat.sentToPrinter is null and chat.sentToManager is null and chat.sentToDesigner is null)
) bb where RowNum>=1 and RowNum<31 
ORDER BY  RowNum asc

我可以做简单的但不能真正地围绕分区连接和select语句.

我真的很感激你的帮助.

提前致谢.

Answer 1

我也遇到了此类问题，但我找到了解决方案，并且对我来说效果很好！

对于此类查询，请使用DB::unprepared() ：

$path = base_path() . "/storage/agency.sql";
$sql = file_get_contents($path);
DB::unprepared(DB::raw($sql));

Laravel 中的所有 SQL 命令默认都是准备好的，但有时您需要在非准备模式下执行命令，因为某些数据库中的某些命令无法在准备模式下运行。