Django:为什么'Class'对象不可迭代

Question

我建了这样的字典列表

lst = [{'name': nameobj, Classobj1: "string", Classobj2: "string"}, \
{'name': nameobj, Classobj1: "string", Classobj2: "string"}]

我正在使用

for dic in lst:
   for k,v in dic:   # here is the line has probloem! What it happens?
       #process

错误消息类似于"Classname"对象不可迭代.

Answer 1

迭代字典只是迭代键,而不是键值对.所以就行了

for k,v in dic:

Python只取一个键,比如Classobj1,并尝试解压缩它以匹配元组k,v.由于Classobj1无法迭代,因此无法解压缩以匹配两个项目,这就是您收到此错误的原因.

要迭代键值对,请使用items()或iteritems():

for k,v in dic.items():