laravel雄辩地总结了来自链接表的多行

Question

我有一个与表Quotes具有一对多关系的QuoteDetails表。

表结构如下所示：

return $this->quotes->with('quotedetails')
    ->orderBy('created_at', 'DESC')->paginate(10);

结果是：

{
   "current_page":1,
   "data":[
      {
         "id":2,
         "subject":"demo",
         "quotedetails":[
            {
               "id":2,
               "quotes_id":2,
               "description":"testing data",
               "total":1080
            },
            {
               "id":3,
               "quotes_id":2,
               "description":"testing",
               "total":180
            }
         ]
      },
      {
         "id":1,
         "subject":"demo",
         "quotedetails":[
            {
               "id":1,
               "quotes_id":1,
               "description":"data",
               "total":360
            }
         ]
      }
   ],
   "per_page":10,
   "prev_page_url":null,
   "to":2,
   "total":2
}

我想包括的总和quotedetails.total而不是QuoteDetails行的完整列表。我不确定该怎么做。

这是我在模型（Quotes）中的查询方式

public function quotedetails(){
        return $this->hasMany('App\Models\QuotesDetail', 'quotes_id', 'id');
    }

我如何获得total总和。

这是我期望的输出

{
   "current_page":1,
   "data":[
      {
         "id":2,
         "subject":"demo link data",
         "quotesum": 1260
      },
      {
         "id":1,
         "subject":"demo",
         "quotesum": 360
      }
   ],
   "per_page":10,
   "prev_page_url":null,
   "to":2,
   "total":2
} 

Answer 1

$query->withCount([
'quotedetail AS quotesum' => function ($query) {
            $query->select(DB::raw("SUM(total) as quotesum"));
        }
    ]);