我试图建立一个电子邮件客户端,但它不起作用:/我试图用SSL连接谷歌imap(没有SSL,我可以做到)代码:
#include "StdAfx.h"
#include "openssl/ssl.h"
#include "iostream"
#include <cstdio>
#include <iostream>
#include <string.h>
#include <errno.h>
#include <sys/types.h>
#include <windows.h>
using namespace std;
#pragma comment(lib, "Ws2_32.lib")
#define BUFSIZE 1024
char buf[BUFSIZE];
char *msg;
WSADATA wsda;
int sock;
struct hostent *host;
struct sockaddr_in server_addr;
short int s_port = 993;
const char *s_ipaddr = "74.125.77.109";
int SSL_library_init();
SSL_METHOD *meth;
int main () {
SSL_load_error_strings();
SSL_library_init();
//RAND_seed(buf, BUFSIZE);
SSL_CTX *sslContext = SSL_CTX_new(SSLv23_client_method());
if (sslContext == NULL)
{
cout << "err\n";
}
SSL *sslConnection = SSL_new(sslContext);
if(sslConnection == NULL)
{
cout << "err\n";
}
WSAStartup(MAKEWORD(2,2), &wsda);
sock = socket(AF_INET, SOCK_STREAM, IPPROTO_IP);
server_addr.sin_family = AF_INET;
server_addr.sin_port = htons(s_port);
server_addr.sin_addr.s_addr = inet_addr(s_ipaddr);
if(server_addr.sin_addr.s_addr == INADDR_NONE)
{
host = NULL;
host = gethostbyname(s_ipaddr);
if(host == NULL)
{
return false;
}
memcpy(&server_addr.sin_addr, host->h_addr_list[0], host->h_length);
}
connect(sock, (struct sockaddr *) &server_addr, sizeof(server_addr));
SSL_set_fd(sslConnection, sock);
SSL_connect(sslConnection);
cout << "Connecting:\n";
SSL_read(sslConnection, buf, sizeof(buf)-1);
cout << buf << "\n";
cout << "Logging-in:\n";
msg = "a1 login emailapp123@gmail.com PASS\n";
SSL_write(sslConnection, msg, strlen(msg));
SSL_read(sslConnection, buf, sizeof(buf)-1);
cout << buf << "\n";
cout << "INBOX\n";
msg = "a2 SELECT INBOX\n";
SSL_write(sslConnection, msg, strlen(msg));
SSL_read(sslConnection, buf, sizeof(buf)-1);
cout << buf << "\n";
system("pause");
}
Run Code Online (Sandbox Code Playgroud)
这就是我收到的:
正在连接:*OK Gimap已准备好接受来自195.150.156.162 y48if37710eei.45的请求
登录:*功能IMAP4rev1 UNSELECT LITERAL + IDLE NAMESPACE QUOTA ID XLIST CHILDREN X-GM-EXT-1 UIDPLUS COMPRESS = DEFLATE a1 OK emailapp123@gmail.com认证(成功)
INBOX
我该怎么做才能建立正确的连接?感谢您的每一条建议:-) Chris
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