如果我有:linkedlist1= 1,2,3,4;和 linkedlist2= 5,6,7;
如果我调用,我能够以这种方式将linkedlist2附加到linkedlist1的末尾:linkedlist2.set(0,9999) 它会变为linkedlist2 = [999,6,7]并 linkedlist1变为[1,2,3,4,9999,7,8];?
那可能吗 ?或者我确实需要另一种结构?
以下代码不起作用:
List<Double> l1 = new LinkedList<Double>(Arrays.asList(1.0,2.0));
List<Double> l2 = new LinkedList<Double>(Arrays.asList(3.0,4.0));
l1.addAll(l2);
System.out.println(l1);
l2.set(0, 9.0);
System.out.println(l1);
Run Code Online (Sandbox Code Playgroud)
OUTPUT:
[1.0, 2.0, 3.0, 4.0]
[1.0, 2.0, 3.0, 4.0]
Run Code Online (Sandbox Code Playgroud)