TypeError:'tuple'对象不可调用

Question

我正在做这本教程,教你自己django 24小时,在第1小时4我被困在这个错误.

Traceback (most recent call last):

  File "C:\Python25\lib\site-packages\django\core\servers\basehttp.py", line 278, in run
    self.result = application(self.environ, self.start_response)

  File "C:\Python25\lib\site-packages\django\core\servers\basehttp.py", line 635, in __call__
    return self.application(environ, start_response)

  File "C:\Python25\lib\site-packages\django\core\handlers\wsgi.py", line 239, in __call__
    response = self.get_response(request)

  File "C:\Python25\lib\site-packages\django\core\handlers\base.py", line 67, in get_response
    response = middleware_method(request)

  File "C:\Python25\Lib\site-packages\django\middleware\common.py", line 56, in process_request
    if (not _is_valid_path(request.path_info) and

  File "C:\Python25\Lib\site-packages\django\middleware\common.py", line 142, in _is_valid_path
    urlresolvers.resolve(path)

  File "C:\Python25\Lib\site-packages\django\core\urlresolvers.py", line 254, in resolve
    return get_resolver(urlconf).resolve(path)

  File "C:\Python25\Lib\site-packages\django\core\urlresolvers.py", line 181, in resolve
    for pattern in self.url_patterns:

  File "C:\Python25\Lib\site-packages\django\core\urlresolvers.py", line 205, in _get_url_patterns
    patterns = getattr(self.urlconf_module, "urlpatterns", self.urlconf_module)

  File "C:\Python25\Lib\site-packages\django\core\urlresolvers.py", line 200, in _get_urlconf_module
    self._urlconf_module = __import__(self.urlconf_name, {}, {}, [''])

  File "c:\projects\iFriends\..\iFriends\urls.py", line 17, in <module>
    (r'^admin/', include('django.contribute.admin.urls'))

TypeError: 'tuple' object is not callable

有谁可以帮助我吗..

url.py

from django.conf.urls.defaults import *

####Uncomment the next two lines to enable the admin:
#### from django.contrib import admin
#### admin.autodiscover()

urlpatterns = patterns('',
    (r'^People/$', 'iFriends.People.views.index') ,
    (r'^admin/', include('django.contrib.admin.urls')), 
    # Example:
    # (r'^iFriends/', include('iFriends.foo.urls')),

    # Uncomment the admin/doc line below and add 'django.contrib.admindocs' 
    # to INSTALLED_APPS to enable admin documentation:
    # (r'^admin/doc/', include('django.contrib.admindocs.urls')),

    # Uncomment the next line to enable the admin:


)

Answer 1

你以某种方式将一些功能设置为一个元组.请编辑问题并粘贴您的urls.py代码,以便我们指出您的错误.

我可以尝试一下狂野的猜测:

File "c:\projects\iFriends\..\iFriends\urls.py", line 17, in <module>
   (r'^admin/', include('django.contribute.admin.urls'))

这不知何故告诉我你错过了第16行的逗号,所以:

16. (r'^/', 'some_stuff....')      # <-- missed comma here
17. (r'^admin/', include('django.contribute.admin.urls'))

只需输入逗号即可.如果不是这样的话,我会发送我的水晶球来保持重要性.粘贴代码.

编辑

好像你已粘贴urls.py了答案.请编辑问题并粘贴urls.py.

无论如何,错误已经改变.你做了什么？在这个新错误中,urls.py找不到了,所以也许你已经重命名了？你改变了运行应用程序的方式吗？

您粘贴的文件不是正在运行的文件.你粘贴url.py和django正在阅读urls.py吗？错误中的代码与您粘贴的代码不匹配!请粘贴正确的文件,即提供错误的文件,或者我们无法帮助.