使用Json.NET将F#序列化为字符串

weg*_*gry 6 serialization f# json json.net

我正在尝试从F#的区分联合转换为字符串序列化而不是默认的"Case":[value]".能够再次反序列化值不是问题.也许可以使用Json.NET ?

// Fsharp 4.1.0
open Newtonsoft.Json // 10.0.3

type HowLame =
| PrettyLame
| SuperLame

type Lame = {
    howLame: HowLame;
}

[<EntryPoint>]
let main argv =
    let lame = { howLame = PrettyLame }
    let ser = JsonConvert.SerializeObject(lame)

    // {"soLame":{"Case":"PrettyLame"}} by default
    printfn "%s" ser

    // Desired
    assert (ser = """{"soLame":"PrettyLame"}""")
    0 // return an integer exit code
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weg*_*gry 6

创建一个自定义的 Json.NET JsonConverter 并使用它来装饰可区分的联合(“枚举样式”)足以让它以我想要的方式工作。其中很大一部分是从@Brian Rogers 的 C# 回答中音译而来的/sf/answers/1564899871/

open System
open Newtonsoft.Json // 10.0.3
open Newtonsoft.Json.Converters

type ToStringJsonConverter () =
    inherit JsonConverter()
    override this.CanConvert objectType = true;

    override this.WriteJson (writer: JsonWriter, value: obj, serializer: JsonSerializer): unit = 
        writer.WriteValue(value.ToString())

    override this.CanRead = false

    override this.ReadJson (reader: JsonReader, objectType: Type, existingValue: obj, serializer: JsonSerializer) : obj =
        raise (new NotImplementedException());

[<JsonConverter(typeof<ToStringJsonConverter>)>]
type HowLame =
| PrettyLame
| SuperLame

type Lame = {
    howLame: HowLame
}

[<EntryPoint>]
let main argv =
    let lame = { howLame = PrettyLame }
    let ser = JsonConvert.SerializeObject(lame)

    // {"howLame":"PrettyLame"}
    printfn "%s" ser

    0 // return an integer exit code
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Car*_*Dev 6

如果您愿意将 DU 设为枚举(通过指定显式值,这可能没问题,因为没有“有效负载”),您可以使用标准StringEnumConverter

#r "../packages/Newtonsoft.Json/lib/net45/Newtonsoft.Json.dll"
open Newtonsoft.Json

type HowLame = PrettyLame=0 | SuperLame=1
type Lame = { howLame: HowLame; }

// in contrast to DUs, enums must be qualified, i.e. Enum.Value
let lame = { howLame = HowLame.PrettyLame }

let settings = JsonSerializerSettings()
settings.Converters.Add(Converters.StringEnumConverter())

let ser = JsonConvert.SerializeObject(lame, settings)
// val ser : string = "{"howLame":"PrettyLame"}"
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