employee = Employee.objects.filter('age' = 99)
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我们假设此查询集为空.
如果我使用employee[0],那将返回索引超出范围错误,那么是否可以在此处使用None作为默认值?
`employee[0] or None`? # This won't work, but this is what I mean.
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如果您只想获得单个实例,请使用get,而不是filter:
employee = Employee.objects.get(age = 99)
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如果这不存在,您将获得一个Employee.DoesNotExist异常,您需要捕获它.如果有一个以上的99岁员工,您将获得一个Employee.MultipleObjectsReturned异常,您可能希望捕获该异常.
如果你感到懒惰,总会有django烦人的get_object_or_None!
from annoying.functions import get_object_or_None
obj = get_object_or_None(Employee, age=99)
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如果你不想使用所有django-annoying,你总是可以添加get_object_or_None到某处,它看起来像这样:
def get_object_or_None(klass, *args, **kwargs):
"""
Uses get() to return an object or None if the object does not exist.
klass may be a Model, Manager, or QuerySet object. All other passed
arguments and keyword arguments are used in the get() query.
Note: Like with get(), a MultipleObjectsReturned will be raised if
more than one object is found.
"""
queryset = _get_queryset(klass)
try:
return queryset.get(*args, **kwargs)
except queryset.model.DoesNotExist:
return None
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在Django> = 1.6上有first方法,所以你可以这样做:
employee = Employee.objects.filter(age=99).first()
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但请注意,只有在知道QuerySet保证返回1或0结果时才有意义.
这应该有效:
employee[0] if employee else None
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