你怎么能测试两个字典在python中与pytest相等

Question

试图断言具有嵌套内容的两个字典与pytest相互相等(顺序无关紧要).什么是pythonic方式呢？

Answer 1

pytest 的魔力足够聪明。通过写作

assert {'a': {'b': 2, 'c': {'d': 4} } } == {'a': {'b': 2, 'c': {'d': 4} } }

您将有一个关于平等的嵌套测试。

Answer 2

不要花时间自己编写这个逻辑。只需使用默认测试库提供的功能即可unittest

from unittest import TestCase
TestCase().assertDictEqual(expected_dict, actual_dict)

Answer 3

我想一个简单的断言相等测试应该没问题：

>>> d1 = {n: chr(n+65) for n in range(10)}
>>> d2 = {n: chr(n+65) for n in range(10)}
>>> d1 == d2
True
>>> l1 = [1, 2, 3]
>>> l2 = [1, 2, 3]
>>> d2[10] = l2
>>> d1[10] = l1
>>> d1 == d2
True
>>> class Example:
    stub_prop = None
>>> e1 = Example()
>>> e2 = Example()
>>> e2.stub_prop = 10
>>> e1.stub_prop = 'a'
>>> d1[11] = e1
>>> d2[11] = e2
>>> d1 == d2
False

Answer 4

General purpose way is to:

import json

# Make sure you sort any lists in the dictionary before dumping to a string

dictA_str = json.dumps(dictA, sort_keys=True)
dictB_str = json.dumps(dictB, sort_keys=True)

assert dictA_str == dictB_str