jim*_*nes 5 c# xml serialization types
我有一个我无法控制的xml文档,它有一个带有自定义数据类型的元素
<foo>
<time type="epoch_seconds">1295027809.26896</time>
</foo>
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我想有一个类可以自动转换为Epoch秒:
[Serializable]
public class Foo
{
public Foo()
{
}
public EpochTime Time { get; set; }
}
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有没有办法定义一个EpochTime类,以便XML序列化器知道在查找XML时使用它type="epoch_time"?如果是这样,我该如何设置WriteXml并ReadXml执行此操作?
正常的方法是简单地用一个行为如您所期望的属性来填充它:
public class EpochTime {
public enum TimeType {
[XmlEnum("epoch_seconds")] Seconds
}
[XmlAttribute("type")] public TimeType Type {get;set;}
[XmlText] public string Text {get;set;}
[XmlIgnore] public DateTime Value {
get { /* your parse here */ }
set { /* your format here */ }
}
}
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另外,你需要:
[XmlElement("time")]
public EpochTime Time { get; set; }
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这是 xml 的完整示例:
using System;
using System.IO;
using System.Xml;
using System.Xml.Serialization;
static class Program
{
static void Main()
{
Foo foo;
var ser = new XmlSerializer(typeof(Foo));
using (var reader = XmlReader.Create(new StringReader(@"<foo>
<time type=""epoch_seconds"">1295027809.26896</time>
</foo>")))
{
foo = (Foo)ser.Deserialize(reader);
}
}
}
public class EpochTime
{
public enum TimeType
{
[XmlEnum("epoch_seconds")]
Seconds
}
[XmlAttribute("type")]
public TimeType Type { get; set; }
[XmlText]
public string Text { get; set; }
private static readonly DateTime Epoch = new DateTime(1970, 1, 1);
[XmlIgnore] public DateTime Value
{
get
{
switch (Type)
{
case TimeType.Seconds:
return Epoch + TimeSpan.FromSeconds(double.Parse(Text));
default:
throw new NotSupportedException();
}
}
set {
switch (Type)
{
case TimeType.Seconds:
Text = (value - Epoch).TotalSeconds.ToString();
break;
default:
throw new NotSupportedException();
}
}
}
}
[XmlRoot("foo")]
public class Foo
{
public Foo()
{
}
[XmlElement("time")]
public EpochTime Time { get; set; }
}
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